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Answer:
IQ scores of at least 130.81 are identified with the upper 2%.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 100 and a standard deviation of 15.
This means that
What IQ score is identified with the upper 2%?
IQ scores of at least the 100 - 2 = 98th percentile, which is X when Z has a p-value of 0.98, so X when Z = 2.054.
IQ scores of at least 130.81 are identified with the upper 2%.
Problem 10
You are correct. The answer is choice C. The cm^3 notation represents cubic centimeters, which is a unit for volume. Think of a 1 cm by 1 cm by 1 cm cube.
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Problem 11
This problem is a bit strange. She borrows money ($100) but then it says she earns $300 per day. It makes no mention of her paying that $100 back, or when it's due back. I'll just assume that she keeps the $100 for the 12 days.
If that assumption is correct, then she'll have y = 300x+100 dollars after x days.
Plug in x = 0 and you'll get y = 100. Plug in x = 12 and you'll end up with y = 3700. Therefore, the two points on this graph are (0,100) and (12,3700).
The only window that has y = 3700 in it is the interval while the other windows are too small. So only choice D is the answer here. In other words, you'll have "yes" on choice D, and "no" on everything else.