Answer:
21.V=1746.1
22.V=1922.7
23.V=54.4
Step-by-step explanation:
V=h*w*l V=pir^2*h
V=12*8*14 . V=pi*4^2*8
V=1344 . V=402.1
V1+V2=1344+402.1=1746.1
V=pi*r^2*h V=2/3*pi*r^3
V=pi*6^2*13 V=2/3*pi*6^3
V=pi*36*13 V=2/3*pi*216
V=1470.3 V=452.4
V1+V2=1470.3+452.4=1922.7
V=1/3pi*r^2*h V=1/3pi*r^2*h
V=1/3pi*2^2*6 V=1/3pi*2^2*7
V=8pi V=28/3pi
V=25.1 . V=29.3
V1+V2=25.1+29.3=54.4
Answer:
73
Step-by-step explanation:
647 - 574
1.) subtract 7 -4 and you get 3 in the ones place.
2.) next you have to do 4 -7 and you can't do that so you take one from the hundreds place and turn the 6 into a 5.
3. make the 4 a 14 and then subtract 14-7 and you get 7 in the tens place
4.) you are then left with 5-5 in the hundreds place which is 0 so your answer is 73
Answer:
no
Step-by-step explanation:
Establish the nth term formula
There is a common difference d between consecutive terms, that is
d = - 5 - (- 9) = - 1 - (- 5) = 3 - (- 1) = 7 - 3 = 4
This indicates the sequence is arithmetic with nth term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = - 9 and d = 4 , then
= - 9 + 4(n - 1) = - 9 + 4n - 4 = 4n - 13
Equate 4n - 13 to 301
4n - 13 = 301 ( add 13 to both sides )
4n = 314 ( divide both sides by 4 )
n = 78.5
Since n is not an integer then 301 is not in the sequence
The correct answer is 0.6 :)
Answer:
Consecutive odd integers are 19 , 21 & 23
Step-by-step explanation:
Let the first 3 consecutive odd intergers be x , (x + 2) and (x + 4).
According to the question,


Eliminating 2x from both the sides,



So, the consecutive odd integers are = 19 , 21 & 23.