m
=
−
2
, (
3,
5
)
Find the value of b
using the formula for the equation of a line.
b
=
11
Now that the values of
m (slope) and b
(y-intercept) are known, substitute them into
y
=
m
x
+
b to find the equation of the line. y
=
−
2
x
+
11
The measure of the angle FEG is probably the same as the measure of the angle FDG. There is nothing saying that EF is parallel to DG, but if so, the measure of the angle FEG is also 50º.
When the diagonals of a trapezium with two parallel bases inside of a circle are drawn, they make the same angle measure with those bases.
Hi there!
x=8
<u><em>1.Subtract the answer with the 3 / subtract the terms:</em></u>
<u><em /></u>
<u><em /></u>
<u><em>2.Divide the two terms:</em></u>
<u><em /></u>
<u><em /></u>
Therefore, x=8
<u><em /></u>
<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>
