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yaroslaw [1]
8 months ago
8

Two friends drive off in different directions from the same place. One heads North at 40 miles per hour, while the other heads E

ast at 20 miles per hour. Complete an equation for the distance between the friends after t hours.
Mathematics
1 answer:
Natalka [10]8 months ago
3 0

An equation for the distance between the friends after time (t) in hours is c = 4t√125.

<h3>How to determine an equation for the distance between the friends?</h3>

In order to determine an equation for the distance between the friends after an amount of time (t) in hours, we would create a mental image of a right-angled triangle because they both head in the opposite (North) and adjacent (East) direction.

Therefore, the distance between them after t hours represent the hypotenuse of a right-angled triangle, which can be calculated by using Pythagorean theorem.

Next, we would determine the distance covered by each friend:

For the first friend (North), we have:

Distance, a = speed × time

Distance, a = 40t

For the second friend (East), we have:

Distance, b = speed × time

Distance, b = 20t

By applying Pythagorean theorem, the distance between the friends after an amount of time (t) is given by:

Distance, c² = a² + b²

Distance, c² = (40t)² + (20t)²

Distance, c² = 1600t² + 400t²

Distance, c² = 2000t²

Distance, c = √(16 × 125t²)

Distance, c = √16t² × √125

Distance, c = 4t√125

<u>Note:</u> The prime factorization of 2000 is 2⁴ × 5³ = 16 × 125.

Read more on distance here: brainly.com/question/28606453

#SPJ1

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Answer:

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And we can use the probability mass function and we got:

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P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576  

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And replacing we got:

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Step-by-step explanation:

Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Solution to the problem  

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=20, p=0.2)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

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Part a

We want this probability:

P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)

And we can use the probability mass function and we got:

P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115  

P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576  

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And adding we got:

P(X \leq 2)=0.0115+0.0576+0.1369 = 0.2061

Part b

We want this probability:

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And using the probability mass function we got:

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Part c

We want this probability:

P(X>3)

We can use the complement rule and we got:

P(X>3) = 1-P(X \leq 3) = 1- [P(X=0)+P(X=1)+P(X=2)+P(X=3)]

P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115  

P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576  

P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369

P(X=3)=(20C3)(0.2)^3 (1-0.2)^{20-3}=0.2054

And replacing we got:

P(X>3) = 1-[0.0115+0.0576+0.1369+0.2054]= 1-0.4114= 0.5886

Part d

The expected value is given by:

E(X) = np

And replacing we got:

E(X) = 20*0.2= 4

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