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jolli1 [7]
1 year ago
5

financial management requires both short-term activities as well as long-term planning such as raising funds.

Business
1 answer:
Vladimir79 [104]1 year ago
8 0

Financial management requires both short-term activities as well as long-term planning such as raising funds.TRUE

Financial management is the workout of handling an agency's budget in a manner that permits it to be successful and compliant with guidelines. That takes each a high-stage plan and boots-on-the-ground execution.

Economic management is the agency characteristic concerned with profitability, fees, coins, and credit, just so the agency may also have the way to carry out its goal as satisfactorily as feasible; the latter is often described as maximizing the rate of the firm for stockholders.

Learn more about Financial management here:-brainly.com/question/989344

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A pharmaceutical company wishes to test the efficacy of a new antidepressant using a double-blind procedure. which alternative c
mamaluj [8]

I guess the correct answer to this question is,

The research assistants would not know which participants were receiving the new drug and which were receiving an inert pill. Also, each patient would not know which type of pill he or she was taking.

3 0
4 years ago
How does education level impact monetary earninas?
larisa86 [58]

Answer:  

He level of income one can earn post-university is perhaps the easiest to measure return on investment in education. ... Therefore, for an employer, the higher the educational requirement, the more money he is willing to pay. Thus, the higher your level of education, the more you are worth in the job market.

Explanation:

5 0
4 years ago
A city is spending $20 million on a new sewage system. The expected life of the system is 40 years, and it will have no market v
Gwar [14]

Answer:

−$28,475,000

Explanation:

AW = −$20,000,000 (A/P, 8%, 40) $600,000= −$2,278,000

CW = −$2,278,000 / 0.08

= −$28,475,000

Therefore If the city's MARR is 8% per year, the capitalized worth of the system is

−$28,475,000

5 0
3 years ago
Read 2 more answers
Outline the benefit of running a business
steposvetlana [31]

Answer:

Explanation:

"Owning and running your own business can be more satisfying and fulfilling than working for someone else. Many successful small business owners find they enjoy the respect they earn from their peers for having the courage to go out on their own. Power. Don't be surprised if power is one of your goals."

7 0
4 years ago
Read 2 more answers
The jackson family is undecided about whether or nara buy a new car of the
ICE Princess25 [194]

The question is incomplete. The complete question is :

The Jackson family is undecided about whether or not to buy a new car. If the probability is .9 that they will buy one, and if the probability is .3 that they will buy a Ford, and if the probability is .4 that they will purchase a car getting more than 20 miles per gallon, what is the probability that they will buy either a car getting more than 20 miles per gallon or a Ford, if all Fords get more than 20 miles per gallon?

Solution :

Given that :

The probability of buying a new car,  P(NC) = 0.9

Probability of buying Ford = 0.3

That is, if Jackson family buy a car that is a ford car, $P(F) = 0.9 \times 0.3$

                                                                                                = 0.27

The probability for getting more than 20 miles per gallon = 0.4

That is if Jackson family buy a car that have more than 20 miles per gallon mileage, $P(20) = 0. 9 \times0.4=0.36$

The conditions

All of the car have more than 20 miles per gallon mileage.

It means that buying a ford car is subset of getting more than 20 miles per gallon.

$P(20 \text{ miles per gallon}\ \cap \ \text{Ford})=P(F)$

Therefore, the probability of buying a car either getting more than 20 miles per gallon or ford = $P(20 \text{ miles per gallon}\ \cup \ \text{Ford})$

Therefore,

$P(20 \text{ miles per gallon}\ \cup \ \text{Ford})=P(20) + P(F) - P(20 \text{ miles per gallon }\cap \ \text{Ford})$

$P(20 \text{ miles per gallon}\ \cup \ \text{Ford})=P(20) + P(F) - P(F)$

$P(20 \text{ miles per gallon}\ \cup \ \text{Ford})=P(20) $

                                                = 0.36

Thus the probability that Jackson family is buying a car either getting more than 20 miles per gallon or ford is 0.36

3 0
3 years ago
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