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abruzzese [7]
1 year ago
3

Question #3) Standard: G.GPE.B.5 * 2 points ; Which equation represents a line parallel to the line whose equation is – 2x + 3y

= -4 and passes through the point (1,3)? (1) y - 3 = -(x - 1) (3) y + 3 = - 3 (x + 1) (2) y – 3 = (x - 1) (4) y + 3 = ? (x + 1) O Option 1 O Option 2 Option 3 O Option 4
Mathematics
1 answer:
ollegr [7]1 year ago
5 0

The line:

-2x+3y=-4

can be written as:

\begin{gathered} -2x+3y=-4 \\ 3y=2x-4 \\ y=\frac{2}{3}x-\frac{4}{3} \end{gathered}

from this form we notice that its slope is 2/3.

We know that two lines are parallel if and only if their slopes are equal, this measn the lie we are looking for has slope 2/3 also.

Once we know the slope of the second line and since we know a point of it we can use the equation of a line:

y-y_1=m(x-x_1)

Plugging the values we have that the equation we are looking for is:

y-3=\frac{2}{3}(x-1)

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Answer:

x = 28

Step-by-step explanation:

If the quadrilaterals are similar, there is a proportionality among their sides:

The top side in the large figure (70) is to the top side in the small figure (10) in the same ratio as the left side (x) in the large figure is to the left side in the small figure (4). This in math terms is written as:

\frac{70}{10} =\frac{x}{4}

We can then solve for the unknown "x" by multiplying both sides by 4:

\frac{70}{10} =\frac{x}{4}\\\frac{70\,*\,4}{10} =x\\x=28

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2 years ago
The graph of $y=ax^2+bx+c$ passes through points $(0,5)$, $(1,10)$, and $(2,19)$. Find $a+b+c$.
MAVERICK [17]

Answer:

a+b+c=10

Step-by-step explanation:

We are given that the graph of the equation:

y=ax^2+bx+c

Passes through the three points (0, 5), (1, 10), and (2, 19).

And we want to find the value of (<em>a</em> + <em>b</em> + <em>c</em>).

First, since the graph passes through (0, 5), its <em>y-</em>intercept or <em>c</em> is 5. Hence:

y=ax^2+bx+5

Next, since the graph passes through (1, 10), when <em>x</em> = 1, <em>y</em> = 10. Substitute:

(10)=a(1)^2+b(1)+5

Simplify:

5=a+b

The point (2, 19) tells us that when <em>x</em> = 2, <em>y</em> = 19. Substitute:

(19)=a(2)^2+b(2)+5

Simplify:

14=4a+2b

This yields a system of equations:

\begin{cases} 5 = a + b \\ 14 = 4a + 2b\end{cases}

Solve the system. We can do so using elimination (or any other method you prefer). Multiply the first equation by negative two:

-10=-2a-2b

Add the two equations together:

(-10)+(14)=(-2a+4a)+(-2b+2b)

Combine like terms:

4 = 2a

Hence:

a=2

Using the first equation:

5=(2)+b\Rightarrow b=3

Therefore, our equation is:

y=2x^2+3x+5

Thus, the value of (<em>a</em> + <em>b</em> + <em>c</em>) will be:

a+b+c = (2) + (3) + (5) = 10

7 0
3 years ago
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