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KengaRu [80]
1 year ago
5

Do the points on the linehave a constant ratio of they-coordinate to the x-co-ordinate for any point onthe line except the y-int

er-cept? Explain your answer.
Mathematics
1 answer:
kvasek [131]1 year ago
8 0
\begin{gathered} \text{the ratio asked is} \\ m=\frac{y}{x},\text{ which is the slope by taking the initial point as the origin} \\ when\text{ the line intercept the y axes, x =0} \\ \text{then } \\ m=\frac{y}{0} \\ \sin ce\text{ its a dividision by zero, the slope is infinite} \\  \end{gathered}\begin{gathered} \text{remember that the slope, in general, is given by} \\ m=\frac{y_2-y_1}{x_2-x_1} \\ \text{where, point A could be A=(x}_1,y_1)andpointBcouldbeB=(x_2,y_2) \end{gathered}\begin{gathered} \text{if you take as point A=(0,0), the slope equation is} \\ m=\frac{y_2}{x_2} \end{gathered}

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Pls help me with trig :)
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Answer:

Step-by-step explanation:

let ∠GEF=x

then ∠GFE=90-x

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4 0
3 years ago
Rewrite the function W= 50+2.3(h-60) in order to express height as a function of weight
OLga [1]
You need to solve the equation for h.

<span>W= 50+2.3(h-60)

Distribute the 2.3.

W = 50 + 2.3h - 138

W = 2.3h - 88

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W + 88 = 2.3h

Switch sides.

2.3h = W + 88

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5 0
3 years ago
In fig if x+y=w+z then prove that AOB is a line.​
frez [133]

Answer:

As Given, x+y=w+z

To Prove: AOB is a line or x+y=180

∘

(linear pair.)

According to the question,

x+y+w+z=360

∘

∣ Angles around a point.

(x+y)+(w+z)=360

∘

(x+y)+(x+y)=360

∘

∣ Given x+y=w+z

2(x+y)=360

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(x+y)=180

∘

Hence, x+y makes a linear pair.

Therefore, AOB is a straight line

4 0
3 years ago
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