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KengaRu [80]
1 year ago
5

Do the points on the linehave a constant ratio of they-coordinate to the x-co-ordinate for any point onthe line except the y-int

er-cept? Explain your answer.
Mathematics
1 answer:
kvasek [131]1 year ago
8 0
\begin{gathered} \text{the ratio asked is} \\ m=\frac{y}{x},\text{ which is the slope by taking the initial point as the origin} \\ when\text{ the line intercept the y axes, x =0} \\ \text{then } \\ m=\frac{y}{0} \\ \sin ce\text{ its a dividision by zero, the slope is infinite} \\  \end{gathered}\begin{gathered} \text{remember that the slope, in general, is given by} \\ m=\frac{y_2-y_1}{x_2-x_1} \\ \text{where, point A could be A=(x}_1,y_1)andpointBcouldbeB=(x_2,y_2) \end{gathered}\begin{gathered} \text{if you take as point A=(0,0), the slope equation is} \\ m=\frac{y_2}{x_2} \end{gathered}

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y = -1/2x + 2

Step-by-step explanation:

y = 2x - 3. The slope here is 2. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal, just flip the slope and change the sign.

slope = 2 or 2/1.....flip it.....1/2....change the sign...-1/2. So our perpendicular line will have a slope of -1/2.

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