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pshichka [43]
3 years ago
7

Eitan randomly selected volcanoes to travel to and study. After traveling, he had seen 13 cinder cone volcanoes, 18 shield volca

noes, and 6 stratovolcanoes. Use the observed frequencies to create a probability model for Eitan randomly selecting one volcano in the world on which to conduct an extensive study.
Mathematics
2 answers:
larisa [96]3 years ago
8 0

Answer:

Probability of selecting one volcano in the world on which to conduct an extensive study is given by

\frac{1}{37}

Step-by-step explanation:

Since we have given that

Number of cinder cone volcanoes = 13

Number of shield volcanoes = 18

Number of strato volcanoes = 6

Total number of volcanoes is given by

13+18+6\\\\=37

So, Probability of getting one volcano in the world on which to conduct an extensive study is given by

\frac{\text{Number of favorable outcomes}}{\text{ Total number of outcomes}}\\\\=\frac{1}{37}

Hence, Probability of selecting one volcano in the world on which to conduct an extensive study is given by

\frac{1}{37}

MAXImum [283]3 years ago
8 0

Answer:

P( cinder cones ) =  13/37

P ( shield ) =  18/37

P ( stratovolcanoes) =  6/37

Step-by-step explanation:

We need to find the total number of volcanoes

13 +18 + 6 = 37

P( cinder cones ) = number of cinder cones/ total = 13/37

P ( shield ) = number of shield /total = 18/37

P ( stratovolcanoes) = number of strato /total = 6/37

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Question 1:

If Jason is pulling with a force of 19 Newtons and his arm is at an angle of 30° with the horizontal.

By resolving Jason's force of pull in the vertical direction, Fy = 19 × Sin 30° = 9.5 Newtons.

The <em>vertical</em> component of Jason's force is 9.5 Newtons.

Question 2:

Also,If Jason is pulling with a force of 14 Newtons and his arm is at an angle of 79° with the <em>horizontal</em>.

By resolving Jason's force of pull in the <em>horizontal</em> direction, Fx = 14 × Cos79° = 2.67 Newtons.

The horizontal component of Jason's force is 2.67Newtons.

Question 3:

If Jason is pulling with a force of 23Newtons and his arm is at an angle of 30° with the <em>horizontal</em>.

By resolving Jason's force of pull in the <em>vertical</em> direction, Fy = 23 × Sin 30° = 11.5Newtons.

The vertical component of Jason's force of pull is, 11.5Newtons.

If the box weighs 24Newtons.

By treating up as the +ve vertical direction and down as the -ve vertical direction,

Therefore, the weight of the box acts in the -ve vertical direction, while Jason's vertical force component acts in the +ve vertical direction.

Therefore, the net force in the vertical direction is = 11.5Newtons + (-24Newtons)

Therefore, the net force in the vertical direction is -12.5Newtons.

Question 4:

If there are two forces at right angles to eachother, one of magnitude, 68 and the other of magnitude, 24.

The resultant force on the object can be obtained by Pythagoras theorem (Triangle law of forces).

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