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Lady bird [3.3K]
1 year ago
5

How many moles of O2 were produced in a decomposition reaction of H2O2 if the pressure was 0.978 atm, the temperature was 27C an

d the volume of O2 gas collected was 0.082L
Chemistry
1 answer:
xxTIMURxx [149]1 year ago
6 0

The number of mole of O₂ produced from the decomposition of H₂O₂ is 0.0033 mole

<h3>How to determine the number of mole of O₂ produced</h3>

We'll begin by obtaining the mole of H₂O₂ that decomposed. This is obatined as follow:

  • Pressure (P) = 0.978 atm
  • Temperature (T) = 27 °C = 27 + 273 = 300 K
  • Volume (V) = 0.082 L
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Mole of H₂O₂ (n) =?

PV = nRT

Divide both sides by RT

n = PV / RT

n = (0.978 × 0.082) / (0.0821 × 300)

n = 0.0033 mole

Finally, we shall determine the number of mole of O₂ produced. This is illustrated below

H₂O₂ -> H₂ + O₂

From the balanced equation above,

1 mole of H₂O₂ decomposed to produce 1 moles of O₂

Therefore,

0.0033 mole of H₂O₂ will also decompose to produce = 0.0033 mole of O₂

Thus, number of mole of O₂ produced from the reaction is 0.0033 mole

Learn more about number of mole:

brainly.com/question/13375719

#SPJ1

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