The number of mole of O₂ produced from the decomposition of H₂O₂ is 0.0033 mole
<h3>How to determine the number of mole of O₂ produced</h3>
We'll begin by obtaining the mole of H₂O₂ that decomposed. This is obatined as follow:
- Pressure (P) = 0.978 atm
- Temperature (T) = 27 °C = 27 + 273 = 300 K
- Volume (V) = 0.082 L
- Gas constant (R) = 0.0821 atm.L/Kmol
- Mole of H₂O₂ (n) =?
PV = nRT
Divide both sides by RT
n = PV / RT
n = (0.978 × 0.082) / (0.0821 × 300)
n = 0.0033 mole
Finally, we shall determine the number of mole of O₂ produced. This is illustrated below
H₂O₂ -> H₂ + O₂
From the balanced equation above,
1 mole of H₂O₂ decomposed to produce 1 moles of O₂
Therefore,
0.0033 mole of H₂O₂ will also decompose to produce = 0.0033 mole of O₂
Thus, number of mole of O₂ produced from the reaction is 0.0033 mole
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