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Norma-Jean [14]
1 year ago
5

Select all that appear in the DOMAIN {(-8,-12),(4,-8), (2, -10),(-10.-16) -16 -12 -10 -8 -2-4

Mathematics
1 answer:
Yuri [45]1 year ago
3 0
Domain of a set of ordered pairs

We know the domain is the set of all x when is represented by ordered pairs: (x, y)

In this case {(-8,-12),(4,-8), (2, -10),(-10.-16) } we can observe that there are four x (the first number of each pair):

Domain = { -8, 4, 2, -10}

<h2>Domain = {-10, -8, 2, 4}</h2>

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Answer:

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Step-by-step explanation:

45 = 10 + 7x

35 = 7x

5 = x

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3 years ago
What's the lowest common multiple of of 2.2 and 5
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8 0
3 years ago
What is the value of \dfrac{d}{dx}\left(\dfrac{2x+3}{3x^2-4}\right) dx d ​ ( 3x 2 −4 2x+3 ​ )start fraction, d, divided by, d, x
stellarik [79]

Answer:

4.

Step-by-step explanation:

We are asked to find the value of expression \frac{d}{dx}(\frac{2x+3}{3x^2-4}) at x=-1.

First of all, we will find the derivative of the given expression using "Quotient Rule of Derivatives" as shown below:

(\frac{f(x)}{g(x)})'=\frac{f'(x)\cdot g(x)-f(x)\cdot g'(x)}{(g(x))^2}

\frac{d}{dx}(\frac{2x+3}{3x^2-4})

\frac{\frac{d}{dx}(2x+3)*(3x^2-4)-(2x+3)*\frac{d}{dx}(3x^2-4)}{(3x^2-4)^2}

\frac{2*(3x^2-4)-(2x+3)*(6x)}{(3x^2-4)^2}

\frac{6x^2-8-12x^2-18x}{(3x^2-4)^2}

\frac{-6x^2-18x-8}{(3x^2-4)^2}

Therefore, our required derivative is \frac{-6x^2-18x-8}{(3x^2-4)^2}.

Now, we will substitute x=-1 in our derivative to find the required value as:

\frac{-6(-1)^2-18(-1)-8}{(3(-1)^2-4)^2}

\frac{-6(1)+18-8}{(3(1)-4)^2}

\frac{-6+18-8}{(3-4)^2}

\frac{4}{(-1)^2}

\frac{4}{1}

4

Therefore, the value of expression \frac{d}{dx}(\frac{2x+3}{3x^2-4}) at x=-1 is 4.

6 0
3 years ago
Which shows this equation in standard form?. 7 – 3(x – y) = 5x + 2. A. 3x – 8y = 5. B. 8x + 3y = 5. C. 8x – 3y = 5. D. 8x – 3y =
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