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Pie
2 years ago
8

Susie is 5 times the age the she was twenty years ago. How old is she now?

Mathematics
2 answers:
AlekseyPX2 years ago
8 0

Answer:

100 yrs old

Step-by-step explanation:

20 times 5

Sliva [168]2 years ago
7 0

Answer:

Susie is 25 years old

Step-by-step explanation:

Let

  • x = the age Susie has now.
  • x - 20 = the age she was 20 years ago.

If Susie is 5 times the age she was twenty years ago, then

x = 5 . (x - 20)

x = 5x - 100

4x = 100

x = 25

Susie is 25 years old, which is 5 times the age she was 20 years ago (25 years - 20 years = 5 years).

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Look at the graph below when did Denise stop walking?
bonufazy [111]

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4 0
2 years ago
The length of a photograph is 1 cm less than twice the width. The area is 91cm^2. find the width and length.
maksim [4K]

Answer:

Width=6.5 cm

Length=12 cm

Step-by-step explanation:

Step 1: Express the lengths and widths

Width=w

Length=l, but 1 cm less than twice the width=(2×w)-1=2 w-1

Step 2: Solve for the length and width

A=L×W

where;

A=area of the photograph

L=length of the photograph

W=width of the photograph

In our case;

A=91 cm²

L=2 w-1

W=w

91=(2 w-1)w

2 w²-w=91

2 w²-w-91=0, is a quadratic equation

solve for w

w={-1±√(-1²-4×2×-91)}/(2×2)

w=(-1±27)/4

w=(27-1)/4=6.5, or (-1-27)/4=-8

Take w=6.5 cm

L=(2×6.5)-1=13-1=12 cm

Width=6.5 cm

Length=12 cm

6 0
2 years ago
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