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miss Akunina [59]
2 years ago
7

At Johnson Elementary School, there are 24 educational staff personnel consisting of the following: 7 male teachers, 16 female t

eachers, plus the principal of the school is a woman named Ruth Klein. Include the Principal as part of the entire educational staff of the school. a) At Johnson Elementary School, in how many ways can a 5-person committee be chosen from the entire educational staff ? Show your work. b) At Johnson Elementary School, if a 5-person committee is chosen at random, what is the probability that it contains exactly 3 men and 2 women chosen from the entire educational staff? You must show how you computed your answer. Round the final answer accurately to 4 decimal places.
Mathematics
1 answer:
elena-s [515]2 years ago
7 0

a. To solve this, we should make a combination

\begin{gathered} nCr=\frac{n!}{r!(n-r)!} \\ 24P5=\frac{24!}{5!(24-5)!}=42504 \end{gathered}

5 person committee can be chosen in 5100480 different ways

b. To find this probability (A), we should use the answer of the last question as the total cases, and the favourable cases will be the shown combinations

P(A)=\frac{7C3\cdot17C2}{42504}

Calculate the combinations

\begin{gathered} 7C3=\frac{7!}{3!(7-3)!}=35 \\ 17C2=\frac{17!}{2!(17-2)!}=136 \\ P(A)=\frac{35\cdot136}{42504}=\frac{4760}{42504}=0.1120 \end{gathered}

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Step-by-step explanation:

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3 years ago
Simplify the following algebraic expression:<br> 4+3 [6z - 5(6 +2z)]
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\huge\text{Hey there!}

\huge\text{4+3 [6z - 5(6 +2z)]}

\huge\text{4+(3)(6z)+(3)(-5(6+2z))}\\\\\rightarrow\huge\text{4+18z+(-30z)+(-90)}

\huge\text{\bf{Combine the like terms if you have any.}}

\huge\text{Like term \#1: 10z \& -30z}\\\\\\\huge\text{Like term \#2: 4 \& -90}

\huge\text{18z + (-30z) + (4 + (-90))}

\huge\text{18z + (-30z) = -12z}\\\\\\\huge\text{4 + (-90) = -86}

\boxed{\boxed{\huge\text{Answer: -12z + (-86)}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

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5 0
3 years ago
Read 2 more answers
Evaluate the integral of the quotient of the cosine of x and the square root of the quantity 1 plus sine x, dx.
VMariaS [17]

Answer:

∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c.

Step-by-step explanation:

In order to solve this question, it is important to notice that the derivative of the expression (1 + sin(x)) is present in the numerator, which is cos(x). This means that the question can be solved using the u-substitution method.

Let u = 1 + sin(x).

This means du/dx = cos(x). This implies dx = du/cos(x).

Substitute u = 1 + sin(x) and dx = du/cos(x) in the integral.

∫((cos(x)*dx)/(√(1+sin(x)))) = ∫((cos(x)*du)/(cos(x)*√(u))) = ∫((du)/(√(u)))

= ∫(u^(-1/2) * du). Integrating:

(u^(-1/2+1))/(-1/2+1) + c = (u^(1/2))/(1/2) + c = 2u^(1/2) + c = 2√u + c.

Put u = 1 + sin(x). Therefore, 2√(1 + sin(x)) + c. Therefore:

∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c!!!

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3 years ago
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Elan Coil [88]
B is correct.
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C. 3(x+1)= 3x+3
D. 2(x+7) = 2x + 14
7 0
3 years ago
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