Answer:
Line LM
Step-by-step explanation:
First, we need to know what the slope is of a line that would be perpendicular to a line with a slope of -5/6. To find this, we take the reciprocal and multiply it by -1. Therefore, the line we are looking for needs to have a slope of 6/5.
Based on the fact that the slope is positive, we can eliminate lines PQ and JK as they have a negative slope. This leaves us with lines LM and NO.
To find out whether or not it is between LM and NO, you could eyeball it by looking at the graph and simply counting which might be faster if you understand how to do that (rise/run), or you can use the pair of coordinates given to you on each line to calculate for slope.
Line LM -
Line NO -
Based on this, we know that line LM is perpendicular to a line that has a slope of -5/6.
<em>If you need help on calculating slope from two points, I'd suggest watching this video: </em><u>https://www.brightstorm.com/math/algebra/linear-equations-and-their-graphs/finding-the-slope-of-a-line-from-2-points-problem-1/#:~:text=Use%20the%20slope%20formula%20to,second%20points%20are%20x2%2C%20y2.</u>
The distance between the two points is 2
Answer:
y = 3 cos(π/5 x) + 5
Step-by-step explanation:
The amplitude is half the difference of the min and max.
A = (8 − 2) / 2
A = 3
The midline is the average of the min and max.
C = (8 + 2) / 2
C = 5
The difference in the x values of the min and max is half the period.
T/2 = 5 − 0
T = 10
The function is a maximum at x = 0, so use cosine.
y = 3 cos(2π/10 x) + 5
y = 3 cos(π/5 x) + 5
Answer:
<u>The critical numer is x = -3/10</u>
Step-by-step explanation:
We need to find the derivative of the function and then equal to zero to get the values of x.
The function is:
Let's take the derivative whit respect of x and equal to zero.
Now, we just need to solve it for x.
<u>The critical numer is x = -3/10</u>
I hope it helps you!