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Answer:
7 1/3 hours
Step-by-step explanation:
We are to assume that the total number of heater-hours required is a constant. That is, the time is inversely proportional to the number of heaters.
If the number of heaters goes up by a factor of 6/4 = 3/2, then the number of hours will go down by the inverse factor: 2/3.
With 6 heaters instead of 4, the time required is (2/3)(11 hours) = 7 1/3 hours.
Answer:
0.5 week
Step-by-step explanation:
The time spent by a pound of meat in this system is given by the average number of pounds of meat on inventory (2500 pounds) divided by the average weekly meat consumption (5000 pounds per week).
The time, in weeks, is:

The average time spent by a pound of meat in production is 0.5 week.
Answer:
The longest braking distance one of these cars could have and still be in the bottom 1% is of 116.94 feet.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The braking distances of a sample of cars are normally distributed, with a mean of 129 feet and a standard deviation of 5.18 feet.
This means that 
What is the longest braking distance one of these cars could have and still be in the bottom 1%?
This is the 1st percentile, which is X when Z has a pvalue of 0.01, so X when Z = -2.327.




The longest braking distance one of these cars could have and still be in the bottom 1% is of 116.94 feet.