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1 year ago

Roger wishes to determine the average high

1 answer:

8 0

Roger's method would not provide relevant results for what he was trying to accomplish because he was calculating average over a 3 month period instead of for a single day.

<h3>How to find the mean temperature?</h3>

Mean/Average of any given data simply means the sum of the given data divided by the sample size of the given data.

Now, when talking about average temperature, it simply means adding the temperatures for the duration you intend to analyze and then dividing the sum by the number of temperatures you added.

However, in this question Roger wants to find the average temperature for any given data and we know the temperatures in a 24-hour day may differ from time to time and as such the mean/average for a particular day would simply be found by adding up temperatures for the day and then dividing by the number of temperatures added.

Thus, Roger's method would not provide relevant results for what he was trying to accomplish because he was calculating average over a 3 month period instead of for a single day.

Read more about Mean Temperature at; brainly.com/question/1456846

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Hello!

Answer:

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Simplify both sides and isolate the variable.

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saveliy_v [14]

The complete question in the attached figure

we know that
the diagonals of a rhombus intersect to form right angles,
so
angle ACE is ----------> (90°-64°)-----------> 26°
ACE is the angle bisector of ACD, this means that ACD is ---------> 26 x 2 = 52°

The diagonals are angle bisectors to the opposite corners
so
ACD = ACB = 52°
and
BCD = 52 x 2 = 104°
For a rhombus, opposite angles are equivalent,
so
BAD = BCD = 104°

the answer is
angle BAD=104°

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vladimir2022 [97]

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Step-by-step explanation:

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VikaD [51]

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$\begin{gathered} y=mx+b \\ m=slope \\ b=y-intercept \\ x-intercept=a \\ x=\frac{y-b}{m} \\ x=\frac{y}{m}-\frac{b}{m} \\ x=\frac{y}{m}-a \\ or \\ y=mx+ma=m(x+a) \end{gathered}$

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$\begin{gathered} y=mx+b \\ m=slope=\theta \\ b=y-intercept \\ y=\theta x+b \\ \end{gathered}$

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