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Dmitriy789 [7]
2 years ago
7

Can you hlep me hhhhhh

Mathematics
2 answers:
Oxana [17]2 years ago
8 0

Answer:

height = 8

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

with hypotenuse = 10 and legs 12 ÷ 2 = 6 and height h , then

h² + 6² = 10²

h² + 36 = 100 ( subtract 36 from both sides )

h² = 64 ( take square root of both sides )

h = \sqrt{64} = 8

hram777 [196]2 years ago
4 0

Answer:

The answer is 8 please Brainlist me

Step-by-step explanation:

6^2+h^2=10^2

36+h^2=100

Solving for h gives 8

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Decide whether the sequence 4,10,20,34,52 ....... is a linear model,
Alecsey [184]

Answer:

Lineal.

Step-by-step explanation:

To determine if the sequence 4,10,20,34,52 ....... is a linear model, a quadratic model or a cubic model, the following mathematical logical reasoning must be carried out:

4 to 10 = +6

10 to 20 = +10

20 to 34 = +14

34 to 52 = +18

Thus, we can see at a glance that the sequence increases 4 numbers in each digit, adding first 6, then 10, then 14 and so on, with which the next numbers in that sequence should be 74 (+22), 100 ( +26), 130 (+30), 164 (+34), and so on.

Therefore, since there is no quadratic or cubic relationship, the sequence is linear.

6 0
3 years ago
How many pounds and ounces are there in 26 oz?
a_sh-v [17]

1 pound = 16 ounces

_ pound = 26 ounces

Multiply 1 × 26 = 26

Divide 26 ÷ 16 = 1.625 or 2

So, 1.625 or 2 pounds will equal to 26 ounces.

Hope this helps :)

5 0
3 years ago
A museum requires a minimum number of chaperones proportional to the number of students on a field trip. The museum requires a m
Stells [14]

Answer: See explanation

Step-by-step explanation:

Here is the complete question:

A museum requires a minimum number of chaperones proportional to the number of students on a field trip. The museum requires a minimum of 3 chaperones for a field trip with 24 students. Which of the following could be combinations of values for the students and the minimum number of chaperones the museum requires? Choose 2 answers.

A. Students: 72

Minimum of chaperones: 9

B. Students: 16

Minimum of chaperones: 2

C. Students: 60

Minimum of chaperones: 6

D. Students: 45

Minimum of chaperones: 5

E. Students: 40

Minimum of chaperones: 8

Since the museum requires a minimum of 3 chaperones for a field trip with 24 students. This means that there will be 24/3 = 8 students per chaperone.

We then divide the number of students given in the question by the number of chaperone to know our answers. This. Will be:

Students: 72

Minimum of chaperones: 9

This will be: 72/9 = 8

Therefore, this is correct.

B. Students: 16

Minimum of chaperones: 2

This will be: 16/2 = 8

This is correct

C. Students: 60

Minimum of chaperones: 6

This will be: = 60/6 = 10.

Therefore, this is wrong

D. Students: 45

Minimum of chaperones: 5

This will be 45/5 = 9

Therefore, this is wrong.

E. Students: 40

Minimum of chaperones: 8

This will be: 40/5 = 8.

Therefore, this is wrong.

Therefore, options A and B are correct.

3 0
3 years ago
Read 2 more answers
Which set of numbers correctly shows all of the factors of 28? 1, 2, 4, 7, 14, 28 1, 2, 7, 14, 28 0, 1, 7, 14, 28 1, 2, 4, 7, 8,
slega [8]

Answer:

1, 2, 4, 7, 14, 28

Step-by-step explanation:

Factors of 28 are the numbers that divide into 28 evenly.

1, 2, 4, 7, 14, 28

3 0
3 years ago
Read 2 more answers
If y-3x=9, 7x+y=25, what is the value of x and y?
lianna [129]

\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

\text{Now, putting y = 9 + 3x in eq(2)}

\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

4 0
2 years ago
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