Use the three steps to solve the problem.

Mathematics

2 answers:

Oksana_A [137]3 years ago

4 0

Answer:

If the second of the three numbers is

, then the first and third are

n- 1 and n + 1 , so we find: 117 = ( n − 1 ) + n + ( n + 1 ) = 3n

Dividing both ends by

3 we find: n = 117/ 3 = 39

So the three numbers are:

38 , 39 , 40

Step-by-step explanation : I hope it helps please don't forget to mark me brainliest . :)

enot [183]3 years ago

4 0

Answer:

38,39,40

Step-by-step explanation:

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A small military base housing 1,000 troops, each of whom is susceptible to a certain virus infection. Assuming that during the c

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Answer:

$I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

Step-by-step explanation:

The rate of infection is jointly proportional to the number of infected troopers and the number of non-infected ones. It can be expressed as follows:

$\frac{dI}{dt}=a*I*(1000-I)$

Rearranging and integrating

$\frac{dI}{dt}=a*I*(1000-I)\\\\\frac{dI}{I*(1000-I)}=a*dt\\\\\int\frac{dI}{I*(1000-I)}=\int a*dt\\\\-\frac{ln(1000/I-1)}{1000}+C=a*t$

At the initial breakout (t=0) there was one trooper infected (I=1)

$-\frac{ln(1000/1-1)}{1000}+C=0\\\\-0,006906755+C=0\\\\C=0,006906755$

In two days (t=2) there were 5 troopers infected

$-\frac{ln(1000/5-1)}{1000}+0,006906755=a*2\\\\-0,005293305+0,006906755=2*a\\a = 0,00161345 / 2 = 0,000806725$

Rearranging, we can model the number of infected troops (I) as

$-\frac{ln(1000/I-1)}{1000}+0,006906755=0,000806725*t\\\\-\frac{ln(1000/I-1)}{1000}=0,000806725*t-0,006906755\\-ln(1000/I-1)=0,806725*t-0.6906755\\\\\frac{1000}{I}-1=exp^{0,806725*t-0.6906755} \\\\\frac{1000}{I}=exp^{0,806725*t-0.6906755}+1\\\\I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$