The lines that are the directrices of the ellipse is B. x = −3.25 and x = 9.25.
<h3>How to calculate the ellipse? </h3>
From the information given, the equation of parabola will be:
= (x - 3)²/5² + (y - 2)²/3² = 1
Hence, h = 3, k = 2, a = 5, b = 3
e = ✓1 - ✓3²/5²
E = 4/5 = 0.8
The directix will be:
x = 3 + 5/0.8
x = 9.25
x = 3 - 5/0.8
x = -3.25
Therefore, lines that are the directrices of the ellipse is x = −3.25 and x = 9.25.
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Answer:
sin θ . tan θ
Step-by-step explanation:
Note : -
sec ( - θ ) = sec θ
Formula / Identity : -
sec θ = 1 / cos θ
sec ( - θ ) - cos θ
= [ 1 / cos θ ] - cos θ
{ LCM = cos θ }
= [ 1 / cos θ ] - [ cos²θ / cos θ ]
= [ 1 - cos²θ ] / cos θ
{ 1 - cos²θ = sin²θ }
= sin²θ / cos θ
{ sin²θ = sin θ . sin θ }
= sin θ . sin θ / cos θ
{ sin θ / cos θ = tan θ }
= sin θ . tan θ
Hence, simplified.
Answer:
x = 10°
Step-by-step explanation:
a). Since, opposite angles of a cyclic quadrilateral are supplementary angles"
Therefore, in cyclic quadrilateral ABDE,
m∠ABD + m∠AED = 180°
110° + m∠AED = 180°
m∠AED = 180° - 110°
= 70°
b). AD = ED [Given]
m∠EAD = m∠AED [Since, opposite angles of equal sides are equal in measure]
m∠EAD = m∠AED = 70°
By triangle sum theorem in ΔABD,
m∠BAD + m∠ABD + m∠ADB = 180°
m∠BAD + 110° + 40° = 180°
m∠BAD = 180 - 150
= 30°
m∠AEB = m∠AED + m∠DAB [By angles addition postulate]
m∠AEB = 70° + 30°
= 100°
By triangle sum theorem in the large triangle,
x° + m∠AEB + m∠EAB = 180°
x° + 100° + 70° = 180°
x = 180 - 170
x = 10°
14 hundreds, 10 tens, and 2 ones.
A.
-1:
(-1,1)
0:
(0, 2)
1:
(1, 4)
2:
(2, 8)
3:
(3,16)b.
To graph the equation, simply go through the points (-2, 0.5), (-1, 1), (0,2), (1,4), (2,8), and (3,16). Make sure you never go below 0 on the x-axis, because there's an asymptote there.
Hope this helps!
