Answer: 33 333,33 per month or 400 000 per year
Step-by-step explanation:
You need 48 000 + 0.035X = 62 000
So ( 62 000 - 48 000 ) / 0.035 = X
Then you can divide X per 12 (months in a year)
And you have your answer per month .
So 33 333,33 total sale per month to have at least as high as the average pay
The first thing we must keep in mind is that there are 2 bags left over.
Therefore, Luis distributed:
534-2 = 532
The number of bags will be:
N = (total amount distributed) / (amount distributed per store)
Substituting we have:
N = (532) / (28)
N = 19
Answer:
Luis distributed milk for 19 stores.
7: $200<3x-y(28) where x represents each kids money out of it and y represents the parents pay.
8: 7.00>(is greater then or equal to) 0.75X + 1.29Y where X is the amount of bagels and Y is the amount of cream cheese containers.
9: $25 + $75>4X where X is the shirts
10: 720-120>(greater then or equal to) 32X where X is the number of people in each row
11: 2400= 2100+ X(1/20) where X is the value of all things sold.
12: 2000<(X7)-668 where X is the amount of cans in one day.
13: 100> 7X - 10Y where X equals the amount of months and Y equals the amount of CD's
14: $80 - $22> (greater than or equal to) 17X where x equals the amount of shirts.
first off sorry it took so long to answer, these long word questions are time consuming and i havent done them in a while so i had to refresh my memory, secondly the equations all end where i say the word "where", thirdly i am absolutely sure of all these answers except for the first one, the first one i am pretty sure i still got it but not 100%.
hope this helps.
Equations can have one solution, but inequalities have infinite solutions.
Hope this helps!
False. Because if it has one then it is consistent.
Source: If a consistent system has an infinite number of solutions, it is dependent . When you graph the equations, both equations represent the same line. If a system has no solution, it is said to be inconsistent. (https://www.varsitytutors.com/hotmath/hotmath.../consistent-and-dependent-systems)
