The axis of symmetry is -b/2a so -(-8)/2(2) = 8/4 which is 2. The axis of symmetry is 2.
Answer:
QR = 7.6 cm
Step-by-step explanation:
By theorem of tangents drawn from an external point to a circle,
"Tangents drawn from an external point to a circle are equal in measure"
By this property,
PQ = PT = 3.8 cm
And PR = PT = 3.8 cm
Since, QR = PQ + PR [By segment addition postulate]
QR = 3.8 + 3.8
QR = 7.6 cm
Answer:
10
Step-by-step explanation:
I got it right
Answer:
y(x)=2x^3-6x^2+ax+b, a and b are constants
Step-by-step explanation:
d2y/dx2=12x-12, integrating both sides we get
dy/dx=6x^2-12x+a, where a is the integration constant.
Again integrating both sides, we get
y(x)=2x^3-6x^2+ax+b, where b is the integration constant
Step-by-step explanation:
We know that the lenght of an arc is pi. Therefore:
pi = 1/2pi*r where r is the radius
r = 2
On one side we have 2 circles, so the lenght of 1 side is 2. The perimeter will be 2*4 = 8.
*Note: the first equation I wrote can be derived from the general equation for calculating the lenght of a circumference known its radius (L = 2 * pi * r).
