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Bingel [31]
3 years ago
14

The polynomial 24x3 − 54x2 + 44x − 99 is factored by grouping. 24x3 − 54x2 + 44x − 99 24x3 + 44x − 54x2 − 99 4x(____) − 9(____)

What is the common factor that is missing from both sets of parentheses? 6x + 11 6x − 11 6x2 + 11 6x2 − 11
please help me
Mathematics
1 answer:
ipn [44]3 years ago
3 0
Factor by grouping is easier to visualize if we factor each group:
<span>24x3 − 54x2 + 44x − 99
= 24x3 + 44x − 54x2 − 99 
=4x(24x^3/(4x)+44x/(4x)) - 9(54x^2/9+99/9)
=4x(6x^2+11) - 9(6x^2+11)
=(4x-9)(6x^2+11)</span>
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347 cm is equal to: 347 m 34.7 m 3.47 m 0.347 m
PolarNik [594]
1m = 100cm therefore 1cm = 0.01m

347 cm = 347 · 0.01 m = 3.47 m
4 0
4 years ago
Jose bought 750 bags of peanuts for $375.00. He intends to sell each bag for $0.15 more than he paid. How much should he charge
svet-max [94.6K]
Answer: $0.65

Explanation: First find how much Jose paid for each bag
$375 / 750
So $0.50 per bag

Now add $0.15 to that
$0.50 + $0.15

That added together is
$0.65
6 0
3 years ago
Find the indicated limit, if it exists. limit of f of x as x approaches 0 where f of x equals 5 x minus 8 when x is less than 0
mariarad [96]

Find Lim f(x) as x->0

for

f(x)=5x-8 ......x<0

f(x)=|-4-x|......x &ge; 0


Clearly

f(0)=|-4-0|=|-4|=4 exists.

The left-hand limit, as x-> 0- is f(0-)=5(0)-8=-8

The right hand limit, as x->0+ is f(0+)=|-4-0|=|-4|=4


Since the left and right limits do not both equal f(0), the limit does not exist.


3 0
3 years ago
Read 2 more answers
Which best describe the relationship between the two lines describe below?
Anna007 [38]

we have

6x+3y=12 -----> line p

Find the slope

3y=-6x+12

y=-2x+4

m=-2

-4x=2y-2 -----> line Q

2y=-4x+2

y=-2x+1

m=-2

therefore

the lines are parallel because their slopes are equal

7 0
1 year ago
In the diagram of PARALLELOGRAM ABCD, segment BE is perpendicular to segment CED, segment DF is perpendicular to BFC and segment
tiny-mole [99]

Answer:

In parallelogram ABCD

FD is perpendicular to BC

BE is perpendicular to CD

Consider triangle BEC and triangle DFC

FC = EC (Given)

Angle BEC = Angle DFC (=90°)

Angle BCE = Angle DCF (common)

Therefore triangle BEC is congruent to triangle DFC (AAS congruency)

DF = BE (CPCT)

Since the altitudes are equal their bases will also be equal

Therefore BC = DC

Therefore BC = DC = AD = AB

Therefore ABCD is a rhombus

Hope this helps!

Mark me as brainliest

3 0
3 years ago
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