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1 year ago

How do you solve 2sin^2θ = 1 ?

Mathematics

1 answer:

Murrr4er [49]1 year ago

5 0

The value of θ is 45 degrees as sin45° is equal to 1/√2.

<h3>What is trigonometric equation?</h3>

Trigonometric equation refers to an equation consists of a number of trigonometric ratios whose angle is unknown.

<h3>What is the ranges of trigonometric angle?</h3>

Generally trigonometric angles are represented by θ. while solving equations we get the values of θ ranges from 0 degree to 90 degrees.

Given, 2sin²θ = 1

solving the equation

sin²θ = 1/2

sinθ = 1/√2

we know sin45° has a specific value 1/√2

sinθ = sin 45°

now, θ = 45°

hence, the solution is θ = 45 degrees.

to know more about trigonometric ratios and values visit

the link: brainly.com/question/29755110

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