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adelina 88 [10]

2 years ago

7

HELP THIS IS DUE TOMORROW, ITS URGENT!!

1 answer:

Nezavi [6.7K]2 years ago

5 0

Each interior angle is 60° because all angles have to equal up to 180° so 180/3 = 60

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(Picture) MULTIPLYING POLYNOMIALS AND SIMPLIFYING EXPRESSIONS PLEASE HELP!!!!

kvv77 [185]

Answer:

Answer: Third option is the right answer.

Step-by-step explanation:

First we the write the expression

$(a+b)(a^{2}+b^{2}-ab)$

Now teacher says that the product of these polynomials will result in the sum of $a^{3}+b^{3}$

Now the teacher ask if we put the value of a = 2x and b = 1 then what will be the expression look like.

$(2x+1)\left [ (2x)^{2}+(1^{2})-(2x)(1)\right ]$

= $(2x+1)(4x^{2}+1-2x)$

So third option is looking like our expression.

3 0

2 years ago

A bag has 6 number tiles numbered one through six. You draw a number tile, replace the tile and draw a second tile. What is the

Ksivusya [100]

Answer:A
explanation : 1/6 x 1/6=1/36=.028 OR 2.8%

3 0

2 years ago

Read 2 more answers

Identify p, b, and a. Do not solve for the unknown.<br><br> 10.9 is what percent of 34?

Rashid [163]

10.9 = x% of 34

10.9 is the amount
x% is the percent
34 is the base

8 0

2 years ago

the moon is about 240000 miles from earth what is this distance written as a whole number multiplied by a power of ten

miskamm [114]

24 x 10^4, the 4 comes from with how many jumps it took to land on a whole number from 240,000.

4 0

2 years ago

Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

7 0

2 years ago