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2 years ago

9

HELP!!! NEED HELP! It is a very confusing lesson

1 answer:

Elenna [48]2 years ago

6 0

2 bags have exactly 42 jellybeans.

Explanation: stem equals the first digit of the number, the stem equals the second digit of the number.
If you see that there is a 4 under the stem, and 2,2,3 under the leaf, that would mean that the numbers are 42, 42, 43

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A pot of boiling water at 212 degrees Fahrenheit on the stove has less thermal energy than a hot tub full of water at 100..4 deg

Mrac [35]

Answer:

False

Step-by-step explanation:

Whichever has more heat (in this case the stove) has more thermal energy

5 0

2 years ago

What is the area of the figure?

irga5000 [103]

Answer:

$50.2 \: {units}^{2}$

Step-by-step explanation:

Area of the shaded region = Area of exterior circle with radius (3 +2 = 5) units - Area of interior circle with radius 3 units

$= \pi {(5)}^{2} - \pi {(3)}^{2} \\ \\ = \pi( {(5)}^{2} - {(3)}^{2} ) \\ \\ = 3.14 \times (25 - 9) \\ \\ = 3.14 \times 16 \\ \\ = 50.24\\ \\ \approx 50.2 \: {units}^{2}$

6 0

3 years ago

20 students to 30 students increased percentages

umka21 [38]

Answer: 66%

Step-by-step explanation: or No Solution

7 0

2 years ago

Read 2 more answers

Solve the equation 2 x 1 1/2 = 46

Makovka662 [10]

Answer: 11 $\neq$ 46

Step-by-step explanation:

simplify

2 * 11/2 = 46

11 =46

The sides are not equal, so it's false.

6 0

2 years ago

If you're good at logarithms please help me with question h and show full working out ty ;)

Tems11 [23]

Answer: $x=\frac{31}{2}$

Step-by-step explanation:

$2log_a(x+2)=log_a(x+9)+log_a(x-3)$

The first thing we are going to do is to get rid of the 2 in front of the first logarithm. To do this, we have the power property that says:

$log_aX^n=nlog_aX$

Basically, the number in front, is the power of the number in the middle.

Let's rewrite this.

$log_a(x+2)^2=log_a(x+9)+log_a(x-3)$

Now, in order to add logarithms with the same base (in this case "a"), we write the same base of the logarithm, and multiply their values.

$log_a(x+2)^2=log_a(x+9)(x-3)$

Multiply the parentheses.

$log_a(x+2)^2=log_a(x^2-3x+9x-27)$

Combine like terms;

$log_a(x+2)^2=log_a(x^2+6x-27)$

Solve the binomial on the left side.

$log_a(x^2+4x+4)=log_a(x^2+6x-27)$

When we have logarithms with same base, we equal their values.

$x^2+4x+4=x^2+6x-27$

Subtract $x^2$

$x^2-x^2+4x+4=x^2-x^2+6x-27\\4x+4=6x-27$

Subtract 6x

$4x-6x+4=6x-6x-27\\-2x+4=-27$

Subtract 4

$-2x+4-4=-27-4\\-2x=-31$

Divide by -2.

$x=\frac{-31}{-2}\\ x=\frac{31}{2}$

5 0

3 years ago