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HACTEHA [7]
3 years ago
14

What is 6 1/3 divied by 1/6

Mathematics
1 answer:
Harrizon [31]3 years ago
4 0

Answer:

38

Step-by-step explanation:

6⅓÷⅙

change 6⅓ to improper fraction

19/3÷1/6

keep the first fraction, change the division sign to multiplication and reciprocate/flip the second fraction

19/3× 6/1

the denominator 3 and numerator 6 will simplify/cancel each other

the new fraction is now: 19/1 × 2/1

there is no need to multiply the denominators because it will still be equal to 1 so we just need to multiply the numerators by each other

19×2=38 OR 38/1 (both answers are the same)

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Please help!
Gemiola [76]

The derivative of f(x) = 2\cdot x^{2}-9 is f'(x) = 4\cdot x.

In this exercise we must apply the definition of derivative, which is described below:

f'(x) =  \lim_{x \to 0} a_n \frac{f(x+h)-f(x)}{h} (1)

If we know that f(x) = 2\cdot x^{2}-9, then the derivative of the expression is:

f'(x) =  \lim_{h \to 0} \frac{2\cdot (x+h)^{2}-9-2\cdot x^{2}+9}{h}

f'(x) = 2\cdot \lim_{h \to 0} \frac{x^{2}+2\cdot h\cdot x + h^{2}-2\cdot x^{2}}{h}

f'(x) = 2\cdot  \lim_{h \to 0} 2\cdot x + h

f'(x) = 4\cdot x

The derivative of f(x) = 2\cdot x^{2}-9 is f'(x) = 4\cdot x.

We kindly invite to check this question on derivatives: brainly.com/question/23847661

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