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HACTEHA [7]
3 years ago
14

What is 6 1/3 divied by 1/6

Mathematics
1 answer:
Harrizon [31]3 years ago
4 0

Answer:

38

Step-by-step explanation:

6⅓÷⅙

change 6⅓ to improper fraction

19/3÷1/6

keep the first fraction, change the division sign to multiplication and reciprocate/flip the second fraction

19/3× 6/1

the denominator 3 and numerator 6 will simplify/cancel each other

the new fraction is now: 19/1 × 2/1

there is no need to multiply the denominators because it will still be equal to 1 so we just need to multiply the numerators by each other

19×2=38 OR 38/1 (both answers are the same)

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Find the slope of the line that passes through (-1, -1) and (91, 93).
alexandr402 [8]

Answer:

= 47/46

Step-by-step explanation:

Given two points on a line, we use the following formula to find the slope

m = (y2-y1)/(x2-x1)

   = (93- -1)/(91 - -1)

    = (93+1)/(91 +1)

   = 94/92

Divide the top and bottom by 2

 = 47/46

6 0
3 years ago
What is the value of g?
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25(g-7)=3\\\\25g-175=3\\\\25g=178\\\\g=\dfrac{178}{25}

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A crowd funding project has received $8350, which is $750 more than 60% of the goal amount. What is the goal amount
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3 years ago
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Describe the solutions for the quadratic equation shown below:
PtichkaEL [24]

The solutions for the quadratic equation 9x² - 6x + 5 = 0 are A. 2 complex roots

To determine the the type of roots the quadratic equation 9x² - 6x + 5 = 0, we use the quadratic formula to find the roots.

So, for a quadratic equation ax + bx + c = 0, the roots are

x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}

With a = 9, b = -6 and c = 5, the roots of our equation are

x = \frac{-(-6) +/- \sqrt{(-6)^{2} - 4 X 9 X 5} }{2 X 9} \\x = \frac{6 +/- \sqrt{36 - 180} }{18} \\x = \frac{6 +/- \sqrt{-144} }{18} \\x = \frac{6 +/- \sqrt{-12} }{18}\\x = \frac{6}{18} +/- i\frac{12}{18} \\x = \frac{1}{3} +/- i\frac{2}{3} \\x = \frac{1 + 2i}{3}  or \frac{1 - 2i}{3}

Since the roots of the equation are (1 + 2i)/3 and (1 - 2i)/3, there are 2 complex roots.

So, the solutions for the quadratic equation 9x² - 6x + 5 = 0 are A. 2 complex roots

Learn more about quadratic equations here:

brainly.com/question/18117039

5 0
3 years ago
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