Please help I have no idea

Can you guys please help me solve this

Delicious77 [7]

Answer:

it didnt load the picture, it doesnt show my guy

Step-by-step explanation:

6 0

3 years ago

Please help solve this question with steps

Orlov [11]

39x^3 = 13*3*x*x*x

-6x^2 = 2*3*x*x*-1

-3x = 3*x*-1

so in all these factorizations, 3*x is common. so 3x is the common factor.

by seperating the common factor,

3x(13x^2 - 2x-1)

will be the factorization.

xy + 5x - 5y - 25

=x (y+5) -5 (y+5)
=(x-5) (y+5)

hope I helped ya!!!

8 0

3 years ago

Subtract. (4/5p+1/2)-(1/4p-3) A: 21/20p-5/2 B: 1/5p-7/2 C: 11/20p+7/2

Leto [7]

Answer:

A

Step-by-step explanation:

I think it's A because it mostly multiplies then adds and subtracts so you get your answer doing this

8 0

2 years ago

The mean annual tuition and fees for a sample of 12 private colleges was 36,800 with a standard deviation of 5,000 . A dotplot s

Ilya [14]

Answer:

The value of the test statistic and degrees of freedom is 2.148 and 11 respectively.

Step-by-step explanation:

Consider the provided information.

The mean annual tuition and fees for a sample of 12 private colleges was 36,800 with a standard deviation of 5,000 .

Thus, n = 12, $\bar x=36800$ σ = 5000

degrees of freedom = n-1 = 12-1 = 11

$H_0: \mu = 33700\ and\ H_a: \mu \neq 33700$

Formula to find the value of z is: $z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}$

Where $\bar x$ is mean of sample, μ is the mean of population, σ is the standard deviation of population and n is number of observations.

$z=\frac{36800-33700}{\frac{5000}{\sqrt{12}}}$

$z=2.148$

Hence, the value of the test statistic and degrees of freedom is 2.148 and 11 respectively.

6 0

3 years ago

You jog 2 kilometers in 12 minutes. Your friend jogs 3 kilometers in 16.5 minutes. Who jogs faster? You jog faster. Your friend

Darya [45]

Answer:

a) Who jogs faster?

Your friend jogs faster because he jogs with a speed of 10.91 km/hr

Step-by-step explanation:

Speed = Distance(km)/Time(hours)

Question 2 How much sooner will the faster jogger finish a five-kilometer race?

Your friend's will finish a 5km race at a speed of 18.18 km/hr

Your speed is :

You jog 2 kilometers in 12 minutes.

Convert 12 minutes to hours

60 minutes = 1 hour

12 minutes = x

x = 12/60

x = 1/5 hour

Your speed is calculated as:

2km/1/5hour

= 2 km ÷ 1/5 hour

= 2 × 5

= 10 km/hr

Your friend's speed is calculated as:

Your friend jogs 3 kilometers in 16.5 minutes.

Convert 16.5 minutes to hours

60 minutes = 1 hour

16.5 minutes = x

x = 16.5/60

x = 0.275 hour

Your speed is calculated as:

3km/0.275 hour

= 10.909090909 km/hr

Approximately = 10.91km/hr

a) Who jogs faster?

Your friend jogs faster because he jogs with a speed of 10.91 km/hr

Question 2 How much sooner will the faster jogger finish a five-kilometer race?

Your friend jogs faster, hence:

3 km = 10.91 km/hr

5km = x

x = 5 × 10.91/3

x = 18.183333333 km/hr

Your friend's will finish a 5km race at a speed of 18.18 km/hr

4 0

3 years ago