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mrs_skeptik [129]
3 years ago
15

Frederick is working on a number puzzle and discovers that the product of the two base numbers is exactly twice as large as the

sum of those same base numbers. Help on this, please?

Mathematics
2 answers:
Effectus [21]3 years ago
7 0
X*y=2(x+y)

This is an equation representing your word problem. X and Y are the two base numbers, assuming they are different.
poizon [28]3 years ago
7 0

Let two base numbers that is any of the digit from [0-9] be x and y.

  It is given that,  the product of the two base numbers is exactly twice as large as the sum of those same base numbers.

→xy=2×(x+y)

There are two variables in the equation , and there is only one equation.So, we have to use Hit and Trial method to evaluate the value of x and y.

 → 0≤ x≤9 and 0≤ y≤9

⇒ Integral Solution of the above equation can be evaluated by drawing the graph  (Drawn the graph using Desmos)

1.⇒ x=4 and , y=4.

2.⇒ x=6 and y=3

3.⇒x=3 and y=6

4.⇒x=0 and y=0

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algol [13]

Answer:

1/4

Step-by-step explanation:

12/4= 3

Each paid $3 but as a fraction 3/12=1/4

8 0
3 years ago
Read 2 more answers
HELP ME NOW>>>>>>>>>>>>>>>>
Nutka1998 [239]

Answer:

3.8

Step-by-step explanation:

1.8 + 3.6 = 5.4

5.4 - 9.2 = 3.8

4 0
3 years ago
Encuentra el numero decimal equivalente a la fracción
Artyom0805 [142]

7/10 = 0.7

198/100 = 1.98

85/100 = 0.85

45/100 = 0.45

1/4 = 0.25

3/2 = 1.5

3/8 = 0.375

1/9 = 0.11111111    ( goes on forever)        ( sigue para siempre )

Hope it Helps!

¡Espero eso ayude!

3 0
3 years ago
A group of students volunteered to finish a task in 25 days .1 Q of students did not come n the work could b completed in 35 day
SpyIntel [72]

Answer:

p=7Q/2

Step-by-step explanation:

Original number of students:

p students to do 1 job in 25 days.

Let r= the rate for 1 student.

pr*25=1

pr*25=1 is the work rate equation for p students.

Lesser number of students:

p-Q students came to do the job and time required was 35 days.

(P-Q)*r*35=1.

The unknowns are p, Q and r

Equate the original number of students and the lesser number of students

pr*25=(P-Q)*r*35

25rp=35rp - 35Qr

Collect like terms

25rp-35rp = -35Qr

Divide both sides by -5

-5rp+7rp=- 7rp

It can be re written as

7rp-5rp=-7Qr

2rp=7Qr

Make p the subject of the formula

p=7Qr/2r

p=7Q/2

p=7Q/2 is the original number of students

-10rp = -35Qr

The system of these two equations can be solved for p. See the THREE unknown

variables, p, r, and Q. You might assume that either r or Q would be a constant.

5 0
3 years ago
I need answers asap​
erma4kov [3.2K]

Answer:

22/24

Step-by-step explanation:

3 0
3 years ago
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