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mrs_skeptik [129]
3 years ago
15

Frederick is working on a number puzzle and discovers that the product of the two base numbers is exactly twice as large as the

sum of those same base numbers. Help on this, please?

Mathematics
2 answers:
Effectus [21]3 years ago
7 0
X*y=2(x+y)

This is an equation representing your word problem. X and Y are the two base numbers, assuming they are different.
poizon [28]3 years ago
7 0

Let two base numbers that is any of the digit from [0-9] be x and y.

  It is given that,  the product of the two base numbers is exactly twice as large as the sum of those same base numbers.

→xy=2×(x+y)

There are two variables in the equation , and there is only one equation.So, we have to use Hit and Trial method to evaluate the value of x and y.

 → 0≤ x≤9 and 0≤ y≤9

⇒ Integral Solution of the above equation can be evaluated by drawing the graph  (Drawn the graph using Desmos)

1.⇒ x=4 and , y=4.

2.⇒ x=6 and y=3

3.⇒x=3 and y=6

4.⇒x=0 and y=0

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Evaluate 16^1/2 and show work​
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4 0
3 years ago
Z varies jointly as x and y. z=60 when x=5 and y=6. find z when x = 7 and y=3
Aneli [31]

Answer:

z = 42

Step-by-step explanation:

The question can be answered in 2 steps as follows:

Step 1: Calculation of the constant of the variation

The equation for the joint variation can be given as follows:

z = cxy ................... (1)

Where;

z = 60

c = constant = ?

x = 5

y = 6

Substituting the values into equation (1) and solve c, we have:

60 = c * 5 * 6

60 = c * 30

c = 60 / 30

c = 2

Step 2: find z when x = 7 and y = 3

Since from Step 1 c = 2, we now use equation (1) and substitute the values into it to find z as follows:

z = 2 * 7 * 3

z = 42

4 0
3 years ago
Determine which function has the greatest rate of change over the interval [0, 2].
ruslelena [56]
Remember that the average rate of change of a function over an interval is the slope of the straight line connecting the end points of the interval. To find those slopes, we are going to use the slope formula: m= \frac{y_{2}-y_{1}}{x_2-x_1}

Rate of change of a:
From the graph we can infer that the end points are (0,1) and (2,4). So lets use our slope formula to find the rate of change of a:
m= \frac{y_{2}-y_{1}}{x_2-x_1}
m= \frac{4-1}{2-0}
m= \frac{3}{2}
m=1.5
The average rate of change of the function a over the interval [0,2] is 1.5

Rate of change of b:
Here the end points are (0,0) and (2,2)
m= \frac{2-0}{2-0}
m= \frac{2}{2}
m=1
The average rate of change of the function b over the interval [0,2] is 1

Rate of change of c:
Here the end points are (0,-1) and (2,0)
m= \frac{0-(-1)}{2-0}
m= \frac{1}{2}
m=0.5
The average rate of change of the function c over the interval [0,2] is 0.5

Rate of change of d:
Here the end points are (0,0.5) and (2,2.5)
m= \frac{2.5-0.5}{2-0}
m= \frac{2}{2}
m=1
The average rate of change of the function d over the interval [0,2] is 1

We can conclude that the <span>function that has the greatest rate of change over the interval [0, 2] is the function a.</span>
4 0
3 years ago
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