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Marina CMI [18]
1 year ago
5

Part A

Mathematics
1 answer:
atroni [7]1 year ago
5 0

Answer:

  0, 2 . . . . . (any pair of consecutive even integers)

Step-by-step explanation:

You want a pair of consecutive even integers such that twice the lesser is 4 less than two times the greater.

<h3>Setup</h3>

Let x represent the lesser of the two even integers. Then the greater is (x+2) and the given relation is ...

  2x = 2(x+2) -4

<h3>Solution</h3>

Simplifying gives ...

  2x = 2x +4 -4

  2x = 2x . . . . . . . true for any even integer x

Any pair of consecutive even integers will satisfy the relation.

  one such pair is 0, 2

     <em>check</em>: 2(2) -4 = 2(0)

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\boxed{\sf \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}

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