Answer:
The sum of all exterior angles of BEGC is equal to 360° ⇒ answer F only
Step-by-step explanation:
* Lets revise some facts about the quadrilateral
- Quadrilateral is a polygon of 4 sides
- The sum of measures of the interior angles of any quadrilateral is 360°
- The sum of measures of the exterior angles of any quadrilateral is 360°
* Lets solve the problem
- DEGC is a quadrilateral
∵ m∠BEG = (19x + 3)°
∵ m∠EGC = (m∠GCB + 4x)°
∵ The sum of the measures of its interior angles is 360°
∴ m∠BEG + m∠EGC + m∠GCB + m∠CBE = 360
∴ (19x + 3) + (m∠GCB + 4x) + m∠GCB + m∠CBE = 360 ⇒ add the like terms
∴ (19x + 4x) + (m∠GCB + m∠GCB) + m∠CBE + 3 = 360 ⇒ -3 from both sides
∴ 23x + 2m∠GCB + m∠CBE = 375
∵ The sum of measures of the exterior angles of any quadrilateral is 360°
∴ The statement in answer F is only true
Answer:
480 students are transported to school each day.
Step-by-step explanation:
Since there are 12 buses and each one of them transports 40 students that means that the total amount of students will be equal to...
12 x 40 = 480
The area of a rectangle is length*width.
The length of this 3x and the width is 2x-3. This means that, to find the area, you need to multiply 3x and 2x-3.
Start by writing out this equation:
A=l*w
Then, plug in your given values:
A= 3x*2x-3 (you can also write it as A= 3*x*2*x-3)
Then, following the order of operations, you start by multiplying. This makes your equation become A = 6x^2 -3. (^2 means squared). It turns into this because 3 * 2 is 6 and x * x is x^2 and you still haven’t used the 3 yet.
After this, there is nothing more that you can do to simplify the equation. Therefore, the area is 6x^2 - 3.
I hope this helped!
Answer:
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