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10 months ago

Growth or decay, and determine the percentage rate of increase or decrease.

Mathematics

1 answer:

NNADVOKAT [17]10 months ago

4 0

The expression y = 660(0.902)ˣ represents a decay , the rate of decrease is 9.8% .

In the question ,

it is given that ,

the the exponential function is y = 660(0.902)ˣ

we need to determine that , the equation represents a growth or decay .

0.902 is the variable that will determine a growth or decay .

Since, 0.902 is less than 1 , so it represents a decay function .

To find the rate we subtract 0.902 from 1

= 1 - 0.902

= 0.098

= 9.8% decrease rate

Therefore , The expression y = 660(0.902)ˣ represents a decay , the rate of decrease is 9.8% .

The given question is incomplete , the complete question is

Identify if it's Growth or Decay , and determine the percentage rate of increase or decrease , the function is y = 660(0.902)ˣ ?

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A caterpillar crawling in a straight line across a coordinate plane starts at point (-3,

Irina18 [472]

9514 1404 393

Answer:

Step-by-step explanation:

In vector form, the equation of point p on the line can be written as ...

p = (-3, -4) +t(25 -(-3), 38 -(-4)) . . . . . for some scalar t

p = (-3, -4) +t(28, 42)

p = (-3, -4) +14t(2, 3)

where t takes on any value between 0 and 1.

If we let t = n/14 for some integer 0 ≤ n ≤ 14, then the coordinates of point p will be integers.

There are 15 values that n can have in the allowed range.

The caterpillar touches 15 points with integer coordinates.

7 0

2 years ago

Do you know the answer toPart A: 25% of 50 = Part B: 25% of 60 = Part C: 50% of 60 = Part D: 75% of 60 = Part E: 75% of 30 = Par

Verdich [7]

Answer:

Part A: 25% of 50 = 12.5

Part B: 25% of 60 = 15

Part C: 50% of 60 = 30

Part D: 75% of 60 = 45

Part E: 75% of 30 = 22.5

Part F: 100% of 22.5 = 22.5

Part G: 10% of 22.5 = 2.25

Part H: 50% of 45.7 = 22.85

Step-by-step explanation:

To find - Do you know the answer to

Part A: 25% of 50 =

Part B: 25% of 60 =

Part C: 50% of 60 =

Part D: 75% of 60 =

Part E: 75% of 30 =

Part F: 100% of 22.5 =

Part G: 10% of 22.5 =

Part H: 50% of 45.7 =

Proof -

Part A :

25% of 50 = $\frac{25}{100} *50$ = $\frac{1}{4}*50$ = 12.5

⇒25% of 50 = 12.5

Part B :

25% of 60 = $\frac{25}{100} *60$ = $\frac{1}{4}*60$ = 15

⇒25% of 60 = 15

Part C :

50% of 60 = $\frac{50}{100} *60$ = $\frac{1}{2}*60$ = 30

⇒50% of 60 = 30

Part D :

75% of 60 = $\frac{75}{100} *60$ = $\frac{75}{10}*6$ = 45

⇒75% of 60 = 45

Part E :

75% of 30 = $\frac{75}{100} *30$ = $\frac{75}{10}*3$ = 22.5

⇒75% of 30 = 22.5

Part F :

100% of 22.5 = $\frac{100}{100} *22.5$ = 22.5

⇒ 100% of 22.5 = 22.5

Part G :

10% of 22.5 = $\frac{10}{100} *22.5$ = 2.25

⇒ 10% of 22.5 = 2.25

Part H :

50% of 45.7 = $\frac{50}{100} *45.7$ = $\frac{1}{2}*45.7$ = 22.85

⇒50% of 45.7 = 22.85

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3 years ago

Jacob scored 85%, 90%, and 74% on his first three tests. Then he scored 99%, 84% and 75% on his next three

AlekseyPX

The average of the first three is 83 (85 + 90 + 74)/3
The average of the next 3 is 86.

The difference is 3

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2 years ago

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AlekseyPX

Answer:

Hyperbola.

Step-by-step explanation:

We start from the function:

$x^{2} +y^{2} -z^{2} =36$

We may get the traces if we cut the surface in planes x=k. This is equivalent to replace x for k:

$k^{2}+y^{2} -z^{2}=36\\y^{2} -z^{2}=36-k^{2}$

The last equation is the equation of an hyperbola, which varies its characteristics depending on K (the plane cut).

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