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inn [45]
2 years ago
6

Which of these stars has the shortest life expectancy?

Physics
1 answer:
Vinvika [58]2 years ago
7 0

A 1Msun star in a closed binary system with a 2Msun star.

Systems in which the two stars are close to each other are called close binary star system.

The most massive stars have the shortest lifespans. The reason is that they have most fuel, they burn it so enormously that their lifetimes are very short. As a 1Msun star in a closed binary system with a 2Msun star becomes the massive star so it has the shortest life expectancy.

a. No, an isolated 1Msun star has not the shortest life expectancy.

b. No, a 1Msun star in a closed binary system with a 0.8Msun star has not the shortest life expectancy.

c. Yes, A 1Msun star in a closed binary system with a 2Msun star has the shortest life expectancy.

Learn more about star from:

brainly.com/question/21521087

#SPJ4

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Question 9 Unsaved A 680-Hz sound wave travels at 340 m/s in air, with a wavelength of 0.5 m. 5 m. 50 m. 500 m. none of the abov
ale4655 [162]

The correct option is 0.5 M

Calculation

Wavelength is defined as the ratio of velocity of a wave to its frequency. It is measure in meters. Mathematically, wavelength is given by the following formula:

Wavelength = wave velocity / frequency

From the details given in the question,

Wavelength =?

Velocity = 340 m/s

Frequency = 680 HZ

Wavelength = 340 /680 = 0.5

Therefore, wavelength = 0.5 M

5 0
3 years ago
Read 2 more answers
PLZ HELP ON #22-26!!!! <br><br>Please explain why and how you got your answer.
AleksAgata [21]
22. a - (vf^2 - vi^2)/(2d) 
a = (0 - 23^2)/(170) 
a = -3.1 m/s^2

23. Find the time (t) to reach 33 m/s at 3 m/s^2
33-0/t = 3 
33 = 3t 
t = 11 sec to reach 33 m/s^2
Find the av velocuty: 33+0/2 = 16.5 m/s
Dist = 16.5 * 11 = 181.5 meters to each 33m/s speed. Runway has to be at least this long. 

24. The sprinter starts from rest. The average acceleration is found from: 
(Vf)^2 = (Vi)^2 = 2as ---> a = (Vf)^2 - (Vi)^2/2s = (11.5m/s)^2-0/2(15.0m) = 4.408m/s^2 estimated: 4.41m/s^2
The elapsed time is found by solving
Vf = Vi + at ----> t = vf-vi/a = 11.5m/s-0/4.408m/s^2 = 2.61s

25. Acceleration of car = v-u/t = 0ms^-1-21.0ms^-1/6.00s = -3.50ms^-2
S = v^2 - u^2/2a = (0ms^-1)^2-(21.0ms^-1)^2/2*-3.50ms^-2 = 63.0m 

26. Assuming a constant deceleration of 7.00 m/s^2
final velocity, v = 0m/s 
acceleration, a = -7.00m/s^2
displacement, s - 92m 
Using v^2 = u^2 - 2as 
0^2 - u^2 + 2 (-7.00) (92) 
initial velocity, u = sqrt (1288) = 35.9 m/s 
This is the speed pf the car just bore braking. 

I hope this helps!! 

5 0
3 years ago
If your speed slows down you will have what acceleration?
vitfil [10]
When speed slows down you have kinetic energy.
8 0
4 years ago
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What is the power generated by a 45 kg person who walks up a flight of 12 stairs, each 30 cm high, in 12 s?
Free_Kalibri [48]
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So, the correct answer is B.
3 0
4 years ago
What kind of model is shown below?
Kay [80]
Still there ain’t no picture
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