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Makovka662 [10]
3 years ago
13

a metal has a density of 8.0g/cm3 a solid cube of mass 1.0kg is made from this metal how long is each side of the cube?

Physics
1 answer:
brilliants [131]3 years ago
8 0

Answer:

5 cm

Explanation:

We are given that,

The density of metal = 8 g/cm^3

The Mass of the Solid Cube = Mass of the metal  = 1 kg = 1000 g

We know that,

Density = Mass / Volume

8 = 1000 / V

V = 1000/8\\V = 125 cm^3

Hence, as the volume of the solid cube is 125 cm^3, its side will be the volume's cube root which is 5 cm

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Explanation:

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3 years ago
Imagine a star very similar to our own Sun in both size and mass. This star moves very slightly back and forth in the sky once e
Inessa05 [86]

Answer:

(c) The planet must have a mass about the same as the mass of Jupiter,

(d) The planet must be closer to the star than Earth is to the Sun.

Explanation:

Astrometry is the ideal method to detect high-mass planets that are close to their star. That is because the gravitational effect that it will have the planet over its host star will be greater. This effect can be seen as a wobble in the star as a consequence of how they orbit a common center of mass¹. The center of mass will be closer to the most massive object, So, in the case of an extrasolar planet with masses like Jupiter (Jovian), this point will be a little bit farther from the star, making the wobble more notable than in a system with a low-mass planet.          

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6 0
3 years ago
Two charges 5 c and 15 c are seperated by 10 cm. what is the electric force between them?
icang [17]

Answer:

6.75×10^13N

Explanation:

The electric force between the charges can be determined using coulombs law which states that 'the force of attraction between two charges is directly proportional to the product of the charges and inversely proportional to the square of their distance between them.

Mathematically, F = kq1q2/r² where;

q1 and q2 are the charges

r is the distance between the charges

F is the force of attraction

k is the coulombs constant

Given q1 = 5C q2 = 15C r = 10cm = 0.1m k = 9×10^9Nm²/C²

Substituting the given values in the formula we have;

F =9×10^9×5×15/0.1²

F = 6.75×10^11/0.01

F = 6.75×10^13N

Therefore the electric force between them is 6.75×10^13N

8 0
3 years ago
An object is 16.0cm to the left of a lens. The lens forms an image 36.0cm to the right of the lens. a) What is the focal length
PSYCHO15rus [73]

Answer:

-2.25

Real and inverted image

Explanation:

u = Object distance =  16 cm

v = Image distance = 36 cm

f = Focal length

Lens Equation

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}=\frac{1}{16}+\frac{1}{36}\\\Rightarrow \frac{1}{f}=\frac{13}{144}\\\Rightarrow f=\frac{144}{13}=11.07\ cm

Focal length of the lens is 11.07 cm. Positive value indicates the lens is a convex lens

Magnification

m=-\frac{v}{u}\\\Rightarrow m=-\frac{36}{16}\\\Rightarrow m=-2.25

Since magnification is negative the image inverted

3 0
3 years ago
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