Question

Ask Your Teacher A coil has an inductance of 3.00 mH, and the current in it changes from 0.200 A to 1.50 A in a time interval of 0.200 s. Find the magnitude of the average induced emf in the coil during this time interval.

Answer 1

Answer:

Magnitude of the average induced emf in the coil $= 0.0195$ Volts

Explanation:

Induced emf in a coil with current flowing through it is can be calculated using the relation given below

$emf = -L\frac{dI}{dt}$ ------------ Equation (1)

Where "L" represents the inductance in H

dI represents the change in current in Ampere

and dt represents the change in time or time period for which the current is flowing in seconds

Given

$L = 3.00$ mH  $= 3 * 10^ {-3}$ H

$I_0 = 0.200$ Ampere

$I_t = 1.50$ Ampere

$t = 0.200$ seconds

Substituting the given values in equation (1) we get -

$emf = - (3 * 10^{-3}) * \frac{1.500 - 0.200}{0.200} \\emf = 0.0195$