The solution in set builder notation is given by = {y:3>y≥-1}
Given the inequalities are,
y-1<2 ............(i)
y+2 ≥ 1 ..............(ii)
Solving the first inequality we get,
y-1 < 2
y-1+1 < 2+1, adding 1 to both sides
y < 3
Solving second inequality we get,
y+2 ≥ 1
y+2-2 ≥ 1-2
y ≥ -1
So the range is 3>y≥-1
So the solution in set builder notation is = {y:3>y≥-1}
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