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tatiyna
3 years ago
8

A frog jumps ( 3/5 feet in the span of 2 2/3 seconds. Find the unit rate, in feet per second, that the frog is moving at. Expres

s any improper fractions as mixed numbers.
Mathematics
1 answer:
Shkiper50 [21]3 years ago
6 0

Answer: 4\dfrac{4}{9}\text{ feet per second}

Step-by-step explanation:

Given: A frog jumps \dfrac35 feet in the span of 2\dfrac23 seconds.

So, distance = \dfrac35 feet , time = 2\dfrac23 seconds = \dfrac83 seconds.

Unit rate of movement = \dfrac{\dfrac83}{\dfrac35}\text{ feet per second}

=\dfrac{40}{9}\text{ feet per second}\\\\=4\dfrac{4}{9}\text{ feet per second}

Unit rate=    4\dfrac{4}{9}\text{ feet per second}

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3 years ago
2x + 5y + 30 = 0 The point ( 5/2 , y) is a solution to the equation shown. What is the value of y? A) -7 B) -5 C) 0 D) 5
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2x + 5y + 30 = 0

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