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3 years ago

What is the 1 in the 110

Mathematics

1 answer:

dezoksy [38]3 years ago

8 0

You can divide 110 by 1 to see how many 1's go in 110:
110/1 = 110

This means that there are 110 1's in 110.

Hope this helps! :)

You might be interested in

Area of a circle how do you do this

Katena32 [7]

Answer:

See below.

Step-by-step explanation:

The area of the circle is given by the formula:

$A=\pi r^2$

From the circle, we can see that the diameter is 14. Thus, the radius must be 14 divided by 2 or 7.

We're also using 3.14 for π. Substitute:

$A=(3.14)(7)^2$

Use a calculator:

$A\approx153.86$

And we're done!

5 0

4 years ago

Read 2 more answers

. A fruit company recently released a new applesauce. By the end of its first year, profits on this product amounted to $24,700

lozanna [386]

Answer:

1) P(x) =14400x+10300 2)y=-4x+19 3) $y=\frac{-2x}{3} -14$ 4) x=-11

(Please check the pictures for better understanding)

Step-by-step explanation:

1) Firstly, let's organize the data. Let the dependent variable x be the years, and the Range P(x) the Profit. So arranging these linear functions y=ax+b and plugging the coordinates for each point (1, 24700) and (4, 67900). Goes:

24,700=x+b

67,900=4x +b

1.1)Solving for b, this Linear System of Equation by the Addition Method goes:

$24,700=x+b*(-4)\\67,900=4x+b\\----------\\-98,800=-4x-4b\\67,900=4x+b\\ -----------\\-30900=-3b\\\frac{3b}{3} =\frac{30900}{3}\\ b=10300$

1.2) Now, let's find the slope based on those two points (1, 24700) and (4, 67900) and using the formula to find the slope:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$m=\frac{67900-24700}{4-1}\\ m=\frac{43200}{3}\\ m=14400$

So now we can write this Linear Equation for the Profit:

P(x) =14400x+10300

2) An equation of the line perpendicular to 4y=x-8 has a slope equal to $m_{2}$ =- $\frac{-1}{m_{1}}$ the line. In this case, an equation perpendicular to 4y=x-8 .

Rearranging the given equation of the line 4y=x-8 goes:

$y=\frac{x}{4} -\frac{8}{4} \\ y=\frac{x}{4}-2$

2.1) The slope of this new line is equivalent to m=-4 since -4 is opposite inverse value for the slope of its perpendicular line (1/4).

If the line passes through the point (6,-5), then this point already belongs to this line.

Then, we can write.

-5=-4(6)+b

-5=-24+b

-5+24=-24+24+b

b=19

Now we can write the function:

y=-4x+19

3) Firstly, let's rearrange the equation. Into a General Equation of the Line y=ax+b

2x+3y=5

-2x+2x+3y=5-2x

3y=5-2x

$\frac{3y}{3} =\frac{5}{3} -\frac{2x}{3}$

$y=\frac{-2x}{3}+\frac{5}{3}$

3.2) Let's find out b, the linear coefficient by plugging the coordinates of the point (-3,-8).

Also, Parallel lines have the same value for the slope such as $m_{1}=m_{2}$

-8=-3(-2/3)+b

-8=2+b

-8-2=2-2+b

b=-10

Then the equation of this parallel line is:

$y=\frac{-2x}{3} -10$

4) Now on this last question, we have to find an equation of the line through the point (-11,-4) perpendicular to another line y=15

Suppose the slope of the first line is $m_{1}$ and the value of the slope of its perpendicular is $m_{2}=\frac{-1}{m_{1}}$

y=15 is a horizontal line with slope equals zero, we can rewrite it as y=0x+15.

Then the slope is zero for horizontal lines.

A perpendicular line to a horizontal line is a vertical one.

In addition to this, a vertical line passes through only one point in the x-axis. Then, there is no horizontal variation. This leads the formula of a slope to an undefinition for Real Set.

$m=\frac{y_{2}-y_{1}}{0}$

The only perpendicular line which passes through the point (-11,-4) to y=15 is the line x=-11.

7 0

3 years ago

What is the area of the cross section if the length is 12 cm and the width is 10 cm?

VARVARA [1.3K]

Answer:

120 cm²

Step-by-step explanation:

From the question;

Length is 12 cm
Width is 10 cm

We are required to determine the area of the cross section;

Note that the cross section is the plane of a solid that remains constant through the solid.
In this case, the cross section is a rectangle whose dimensions are 12 cm by 10 cm.

But Area of a rectangle = Length × Width

Therefore;

Area of cross section = 12 cm × 10 cm

= 120 cm²

Thus, area of the cross section is 120 cm²

6 0

4 years ago

The back of Tom's property is a creek. Tom would like to enclose a rectangular area, using the creek as one side and fencing for

ICE Princess25 [194]

Answer:

76,050 ft²

Step-by-step explanation:

If the area must be rectangular, let L be the length of the side opposite to the creek, and S be the length of the remaining two sides.

The perimeter of the fencing and the area of the pasture are:

$780 = L+2S\\A= LS\\\\L=780-2S\\A=-2S^2+780S$

The value of S for which the derivate of the area function is zero is the length of S that maximizes the area of pasture:

$\frac{dA}{dS}=0=-4S+780\\S= 195\\L=780-(2*195)=390$

The maximum possible area is:

$A_{MAX}=390*195=76,050\ ft^2$

6 0

4 years ago

Question 8 Find the unit vector in the direction of (2,-3). Write your answer in component form. Do not approximate any numbers

slamgirl [31]

Answer:

The unit vector in component form is $\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$ or $\hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j$ .

Step-by-step explanation:

Let be $\vec u = (2,-3)$ , its unit vector is determined by following expression:

$\hat {u} = \frac{\vec u}{\|\vec u \|}$

Where $\|\vec u \|$ is the norm of $\vec u$ , which is found by Pythagorean Theorem:

$\|\vec u\|=\sqrt{2^{2}+(-3)^{2}}$

$\|\vec u\| = \sqrt{13}$

Then, the unit vector is:

$\hat{u} = \frac{1}{\sqrt{13}} \cdot (2,-3)$

$\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$

The unit vector in component form is $\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$ or $\hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j$ .

6 0

3 years ago