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schepotkina [342]
3 years ago
6

How do you find the sum of a geometric series?!!!

Mathematics
1 answer:
Ksivusya [100]3 years ago
6 0

Answer:

To find the sum of an infinite geometric series having ratios with an absolute value less than one, use the formula, S=a11−r , where a1 is the first term and r is the common ratio.

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Is 73 a prime number
lora16 [44]
Hi there, 

73 indeed a prime number 

A prime number<span> (or a </span>prime) is a natural number<span> greater than 1 that has no positive divisors other than 1 and itself. A </span>natural number<span> greater than 1 that is not a </span>prime number<span> is called a composite </span><span>number!</span>
6 0
3 years ago
I need this quick!!What is the surface area of the square pyramid?<br> square units
AlexFokin [52]

Answer:

16

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Use pascal's triangle to expand the following binomial expression <br>1.(2k-1/3)⁶​
Gwar [14]

9514 1404 393

Answer:

  64k^6 -64k^5 +(80/3)k^4 -(160/27)k^3 +(20/27)k^2 -(4/81)k +1/729

Step-by-step explanation:

The row of Pascal's triangle we need for a 6th power expansion is ...

  1, 6, 15, 20, 15, 6, 1

These are the coefficients of the products (a^(n-k))(b^k) in the expansion of (a+b)^n as k ranges from 0 to n.

Your expansion is ...

  1(2k)^6(-1/3)^0 +6(2k)^5(-1/3)^1 +15(2k)^4(-1/3)^2 +20(2k)^3(-1/3)^3 +...

     15(2k)^2(-1/3)^4 +6(2k)^1(-1/3)^5 +1(2k)^0(-1/3)^6

  = 64k^6 -64k^5 +(80/3)k^4 -(160/27)k^3 +(20/27)k^2 -(4/81)k +1/729

7 0
2 years ago
Consider the following system of equations.
Sidana [21]
Y = 6x - 6  therefore   y - 6x = -6
y - 6x = 5 
so:
-6 ≠ 5
There is no solution to this system.
==========================
\left \{ {{y=6x-6} \atop {y-6x=5}} \right.  \\  \left \{ {{6x-y=6} \atop {-6x+y=5 }} \right.  \\ 0 \neq 11
6 0
3 years ago
−34(8x+12)=3(x−3) <br> What does x equal?<br><br> Can someone help me solve this ASAP?!?!
IrinaVladis [17]

Answer:

x= −399 /75

Explanation:

Step 1:

−34(8x+12)=3(x−3)

(−34)(8x)+(−34)(12)=(3)(x)+(3)(−3)(Distribute)

−272x+−408=3x+−9

−272x−408=3x−9

Step 2:

−272x−408−3x=3x−9−3x

−275x−408=−9

Step 3:

−275x−408+408=−9+408

−275x=399

Step 4:

−275x

−275

=

399

−275

8 0
3 years ago
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