SO what you need to do is:
<span>Start with |f(x) - 3| < 0.4
and plug in f(x) = x+1
to get
|f(x) – 3| < 0.4
|x+1 – 3| < 0.4
|x - 2| < 0.4
-0.4 < x - 2 < 0.4
-0.4+2 < x < 0.4+2
1.6 < x < 2.4
So delta would be 2.3
Hope this is what you were looking for
</span>
The commutative property of addition
Answer:
<h2>y = 2x - 11</h2>
Step-by-step explanation:



Answer:
- Prime: 3
- GCF: 1
- Factoring Trinomials: 4
- Difference of Squares: 2
- Perfect Square Trinomial (PST): 5
Step-by-step explanation:
1. Each term has an even coefficient, so a factor of 2 can be removed:
2(3x^2 +7x -15)
The remaining quadratic factor is prime.
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2. Each of these two terms is a square, so this is the difference of two squares.
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3. This cubic has one irrational negative real root. It is prime.
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4. This trinomial factors in the usual way: (x +15)(x -2). It is factored by "factoring trinomials."
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5. The magnitude of the x-coefficient is double the square root of the (positive) constant, so this is a perfect square trinomial.