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Andrej [43]
1 year ago
8

Find the 21st term in the arithmetic sequence. 3, 7, 11, 15, 19, ...

Mathematics
1 answer:
NNADVOKAT [17]1 year ago
5 0

The 21st term of the given arithmetic sequence is 83. The nth term of an arithmetic sequence is applied to find the required value where n = 21.

<h3>What is the nth term of an arithmetic series?</h3>

The nth term of an arithmetic sequence is calculated by the formula

aₙ = a + (n - 1) · d

Here the first term is 'a' and the common difference is 'd'.

<h3>Calculation:</h3>

The given sequence is an arithmetic sequence.

3, 7, 11, 15, 19, ....

So, the first term in the sequence is a = 3 and the common difference between the terms of the given sequence is d = 7 - 3 = 4.

Thus, the required 21st term in the sequence is

a₂₁ = 3 + (21 - 1) × 4

⇒ a₂₁ = 3 + 20 × 4

⇒ a₂₁  = 3 + 80

∴ a₂₁  = 83

So, the 21st term in the given arithmetic sequence is 83.

Learn more about the arithmetic sequence here:

brainly.com/question/6561461

#SPJ1

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Homework Progress 23 / 39 Marks Work out 83 +52​
antoniya [11.8K]

Answer:

2 1/25  or 2.04

Step-by-step explanation:

8 ^ 1/3 + 5 ^ (-2)

Rewriting

(2^3) ^ 1/3 + 1/5 ^2

2 + 1/25

2 1/25

2.04

4 0
3 years ago
Read 2 more answers
Find the distance between (2, 2) and (-4, 4). Round answer to the nearest tenth.
Naya [18.7K]

Answer:

6.3

Step-by-step explanation:

First off, we need the distance formula, which is:

\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

If we plug in the points, we get:

\sqrt{(-4 - 2)^2 + (4 - 2)^2}

If we simplify everything under the square root, we get:

\sqrt{(-6)^2 + (2)^2}

\sqrt{36 + 4}

\sqrt{40}

In decimal, the answer is 6.3

6 0
3 years ago
Find the sum of the following series
leonid [27]

Answer:

They are in A. P so the sum will be 2380

4 0
2 years ago
SOLVE EACH SYSTEM USING SUBSTITUTION
NNADVOKAT [17]
1. since the equations equal each other 
2x+19=x+7
-x        -x
x+19=7
  -19  -19
x= -12
sub into y= x+7
y= -12+7
y= -5

2. x+2y=-7
<span>x+y+23=0
i don't know what the second equation is equal to, i'll assume 0

2y=x-7
y=1/2x-7/2
sub this into x+y+23=0
x+1/2x-7/2+23=0
3/2x+39/2=0
       -39/2   -39/2
3/2x= -39/2
x=-39/2 / 3/2
x= -13
sub into y=1/2x-7/2
y=1/2(-13)-7/2
y= -10

3. </span>x+5y=2
<span>x=-4y+5
</span>sub x=-4y+5 into x+5y=2
-4y+5+5y=2
y+5=2
  -5  -5
y= -3
sub y =-3 into x =-4y+5
x=-4(-3)+5
x= 17

4. 3x+y=9
<span>y=-5x+9
</span>sub -5x+9 into 3x+y=9
3x+(-5x+9)=9
3x-5x+9=9
-2x+9=9
     -9  -9
-2x=0
x=0
sub into y=-5x+9
y=-5(0)+9
y=9

3 0
3 years ago
Who knows the Babylonian method, and can help me!<br> **see picture below**
PSYCHO15rus [73]
This is an iteration method for finding the square root.

The ? is also your first initial guess.

? = 10.5

The iteration formula for the square root is actually.

√n =      (x + n/x)÷2.

Where x is your guess.
3 0
3 years ago
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