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Andrej [43]
1 year ago
8

Find the 21st term in the arithmetic sequence. 3, 7, 11, 15, 19, ...

Mathematics
1 answer:
NNADVOKAT [17]1 year ago
5 0

The 21st term of the given arithmetic sequence is 83. The nth term of an arithmetic sequence is applied to find the required value where n = 21.

<h3>What is the nth term of an arithmetic series?</h3>

The nth term of an arithmetic sequence is calculated by the formula

aₙ = a + (n - 1) · d

Here the first term is 'a' and the common difference is 'd'.

<h3>Calculation:</h3>

The given sequence is an arithmetic sequence.

3, 7, 11, 15, 19, ....

So, the first term in the sequence is a = 3 and the common difference between the terms of the given sequence is d = 7 - 3 = 4.

Thus, the required 21st term in the sequence is

a₂₁ = 3 + (21 - 1) × 4

⇒ a₂₁ = 3 + 20 × 4

⇒ a₂₁  = 3 + 80

∴ a₂₁  = 83

So, the 21st term in the given arithmetic sequence is 83.

Learn more about the arithmetic sequence here:

brainly.com/question/6561461

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Simplify the following expression. 3 2/5x3(-7/5)
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The simplified expression of 32/5 x 3(-7/5) is  -672/25

<h3>How to simplify the expression?</h3>

The mathematical expression is given as:

32/5 x 3(-7/5)

Evaluate the product of 3 and -7/5

32/5 x 3(-7/5) =  32/5 x -21/5

Evaluate the product of 32 and -21

32/5 x 3(-7/5) =  672/5 x -1/5

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