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Sati [7]
3 years ago
10

What is (2+y)³ written out? 8 + 12y + 6y² + y³ 6 + 8y + 4y² + y³

Mathematics
2 answers:
AveGali [126]3 years ago
7 0
\boxed{(2+y)^3-cube\ the\ sum\ of\ the\ numbers\ 2\ and\ y}

Use:\ (a+b)^3=(a+b)(a+b)(a+b)=a^3+3a^2b+3ab^2+b^3\\----------------------------\\(2+y)^3=2^3+3\cdot2^2\cdot y+3\cdot2\cdot y^2+y^3=8+3\cdot4y+6y^2+y^3\\\\=8+12y+6y^2+y^3\\========================================

8+12y+6y^2+6y^3+8y+4y^2+y^3\\=8+(12y+8y)+(6y^2+4y^2)+(6y^3+y^3)\\=8+20y+10y^2+7y^3



geniusboy [140]3 years ago
6 0
(2+y)3

=(2+y)*(2+y)*(2+y)

=(2+y)(y2+4y+4)

=(2)(y^2)+(2)(4y)+(2)(4)+(y)(y^2)+(y)(4y)+(y)(4)

=2y^2+8y+8+y^3+4y^2+4y

=y^3+6y^2+12y+8

-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-

8 + 12y + 6y² + y³ 6 + 8y + 4y² + y³

Combine Like Terms:

=8+12y+6y^2+6y^3+8y+4y^2+y3

=(6y^3+y^3)+(6y^2+4y^2)+(12y+8y)+(8)

=7y^3+10y^2+20y+8



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7 0
3 years ago
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Complete the set of ordered pairs for the relation.
Nonamiya [84]

The set of ordered pairs are (-2,18),(-1,20),(0,22),(1,24),(2,26)

Step-by-step explanation:

Given that the relation \{(x, y): y=2(x+11) \text { and } x \in(-2,-1,0,1,2)\}

To find the set of ordered pairs, let us substitute the value for x in the relation y=2(x+11)

For x=-2,

\begin{aligned}y &=2(-2+11) \\&=2(9) \\y &=18\end{aligned}

The ordered pair is (-2,18)

For x=-1,

\begin{aligned}y &=2(-1+11) \\&=2(10) \\y &=20\end{aligned}

The ordered pair is (-1,20)

For x=0,

\begin{aligned}y &=2(0+11) \\&=2(11) \\y &=22\end{aligned}

The ordered pair is (0,22)

For x=1,

\begin{aligned}y &=2(1+11) \\&=2(12) \\y &=24\end{aligned}

The ordered pair is (1,24)

For x=2,

\begin{aligned}y &=2(2+11) \\&=2(13) \\y &=26\end{aligned}

The ordered pair is (2,26)

Thus, the set of ordered pairs is (-2,18),(-1,20),(0,22),(1,24),(2,26)

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4 years ago
Transforming the graph of a function by shrinking or stretchingGraph (a)
tensa zangetsu [6.8K]

ANSWER

EXPLANATION

If g(x) is the transformation of f(x) as follows,

g(x)=f(ax)

Then g(x) is a horizontal compression (if a > 1) or stretch (if a < 1) of f(x). The rule to map each point is,

(x,y)\to(x/a,y)

In this case, this is a stretch so the point (-2, 2) maps to the point (-4, 2) and the origin is the same. Join these two points with a line and we get the graph of f(¹/₂x).

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1 year ago
The table represents a linear function.<br> What is the slope of the function?
TEA [102]

Answer:

-4

Step-by-step explanation:

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We take any two points from the table and compute the slope or  rise/ run between them— let is take points (-4, -2) and (-2, -10).

The slope m of the line joining the points is

m=\dfrac{\Delta y }{\Delta x } =\dfrac{-2-(-10)}{-4-(-2)} \\\\\boxed{m=-4}

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