Answer:
Hence proved △ABE∼△CBF.
Step-by-step explanation:
Given,
ABCD is a parallelogram.
BF ⊥ CD and
BE ⊥ AD
To Prove : △ABE∼△CBF
We have drawn the diagram for your reference.
Proof:
Since ABCD is a parallelogram,
So according to the property of parallelogram opposite angles are equal in measure.
⇒1
And given that BF ⊥ CD and BE ⊥ AD.
So we can say that;
⇒2
Now In △ABE and △CBF
∠A = ∠C (from 1)
∠E = ∠F (from 2)
So by A.A. similarity postulate;
△ABE∼△CBF
F(x) = 8 - 10x
g(x) = 5x + 4
Finding (fg)(-2).
First let us find fg(x), this is the same as f(g(x))
f(g(x))
f(5x + 4)
Recall, f(x) = 8 - 10x, therefore f(5x + 4) would be such that anywhere we see x in the f(x), we replace it with 5x + 4
f(x) = 8 - 10x
f(5x +4) = 8 - 10(5x + 4)
= 8 - 50x - 40
= -50x + 8 - 40
= -50x - 32
f(g(x)) = fg(x) = -50x - 32
fg(-2) = -50*(-2) - 32 = 100 - 32 = 68
Therefore fg(-2) = 68
I hope this helped.
Step-by-step explanation:
Okay! To do this you need to have x on one side (isolate the variable) and also combine like terms. Like terms are terms with the same exponent and variable, like 8x and 6x.
8x+1=-6x-2 To combine like terms here we have to move -6x to the other side of the equation by adding it (using inverse operations). 8x+6x=14x
14x+1=-2 now subtract 1 from both sides.
14x=-3
Divide both sides by 14 and x=-3/14
Brainliest? :)
if you add them all its 340 and the square number is 9
