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Sati [7]
3 years ago
10

What is (2+y)³ written out? 8 + 12y + 6y² + y³ 6 + 8y + 4y² + y³

Mathematics
2 answers:
AveGali [126]3 years ago
7 0
\boxed{(2+y)^3-cube\ the\ sum\ of\ the\ numbers\ 2\ and\ y}

Use:\ (a+b)^3=(a+b)(a+b)(a+b)=a^3+3a^2b+3ab^2+b^3\\----------------------------\\(2+y)^3=2^3+3\cdot2^2\cdot y+3\cdot2\cdot y^2+y^3=8+3\cdot4y+6y^2+y^3\\\\=8+12y+6y^2+y^3\\========================================

8+12y+6y^2+6y^3+8y+4y^2+y^3\\=8+(12y+8y)+(6y^2+4y^2)+(6y^3+y^3)\\=8+20y+10y^2+7y^3



geniusboy [140]3 years ago
6 0
(2+y)3

=(2+y)*(2+y)*(2+y)

=(2+y)(y2+4y+4)

=(2)(y^2)+(2)(4y)+(2)(4)+(y)(y^2)+(y)(4y)+(y)(4)

=2y^2+8y+8+y^3+4y^2+4y

=y^3+6y^2+12y+8

-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-

8 + 12y + 6y² + y³ 6 + 8y + 4y² + y³

Combine Like Terms:

=8+12y+6y^2+6y^3+8y+4y^2+y3

=(6y^3+y^3)+(6y^2+4y^2)+(12y+8y)+(8)

=7y^3+10y^2+20y+8



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The graph will cross at the coordinates (-2, 9)

<h3>How to solve equations?</h3>

y = 3x + 15

y = 3 - 3x

y = 3x + 15

Hence,

when x = 2

y = 3(2) + 15 = 21

when x = 0

y = 3(0) + 15 = 15

y = 3 - 3x

when x = 2

y = 3 - 3(2)

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y = -3

when x = 0

y = 3 - 3(0)

y = 3

Therefore, let's check if the equation will cross.

y = 3x + 15

y = 3 - 3x

using substitution,

3 - 3x = 3x + 15

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x = -12 / 6

x = -2

y = 3 - 3(-2)

y = 3 + 6

y = 9

Therefore, the graph will cross at the coordinates (-2, 9)

learn more on equations here: brainly.com/question/19297665

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