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iren2701 [21]
3 years ago
12

2. How many ounces of Ceylon tea worth $1.50 per ounce

Mathematics
1 answer:
gregori [183]3 years ago
4 0

Answer: How many ounces of ceylon tea worth 1.50 per ounce and how many ounces of formosa tea worth 2.00 per ounce must be mixed to obtain a mixture of 8 ounces that is worth 1.85 per ounce

Equation:

1.5c + 2f = 1.85*8

c + f = 8

Modify:

1.5c + 2f = 1.85*8

2c + 2f = 16

Subtract and solve for "c":

0.5c = 1.2

c = 2.4 ounces (amt. of ceylon tea needed)

Solve for "f":: c + f = 8, so f = 5.2 ounces

Step-by-step explanation:

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svetlana [45]

Answer:27

Step-by-step explanation:first you need 40 x 12 for the area for your gravel

so 480 divided by 18 = about 27

3 0
4 years ago
Please help this is due in 20 mins, I will give brainliest
eduard

Answer:

L = 5\sqrt{10}

Step-by-step explanation:

use Pythagorean Theorem:

L² + (5\sqrt{2})² = (10\sqrt{3})²

L² + 25(2) = 100(3)

L² + 50 = 300

L² = 250

L = \sqrt{250} = \sqrt{25} · \sqrt{10} = 5\sqrt{10}

6 0
3 years ago
Read 2 more answers
What polynomial can be factored to give (a + 4) ( a - 4) ?​
iragen [17]

Answer:

(a+4)(a-4)=a²-4²   ITS LIKE THIS BECAUSE ITS AN IDENTITY,

               ⇒a²-16

Even when we solve it by the regular method of solving polynomials we get a²-16 as answer as there and thats the proof for the identity.

(a+b)(a-b)=a(a-4)+4(a-4)

⇒a²-4a+4a-16

⇒a²-16[NOTE:-4a+4a=0]

Thus we can see that a²-16 is the answer we get when we try to solve it by regular polynomial solution tooo.

And a²-16 is the polynomial from which we get (a+4)(a-4)

8 0
3 years ago
What is the value of 3 in 6035
Sveta_85 [38]
6035 =

6000 + 30 + 5

So I would say 3's value is tenths.
3 0
4 years ago
HELPPPP!!! ASAPPP!!!
erastova [34]

Answer:

A) sum = (180)(20) = 3600°

Step-by-step explanation:

The formula for the sum of interior angles for any polygon is (n-2) x 180° with n being the number of sides the polygon has.

We can just plug in 22 into the equation to get our answer:

(22-2) x 180°

= (20) x 180°

= 3600

7 0
3 years ago
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