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inna [77]
1 year ago
5

A manufacturing company currently uses 15 workers to load and unload trucks. Each worker can move an average of 15 boxes per min

ute. A robotics firm has built a robot that can load and unload boxes at the rate of 21 boxes per minute. How many robots will it take to do the same job as the 15 humans?
Mathematics
1 answer:
goblinko [34]1 year ago
8 0
Answer:

It will take 11 robots to do the same job as the 15 humans

Explanation:

Given:

<em>Workers in use = 15</em>

<em>Each worker can move an average of 15 boxes per minute.</em>

<em>A robot has been built that can move an average of 21 boxes per minute</em>

15 worker would move:

15 * 15 boxes = 225 boxes per minute.

The number of robots it will take to move 225 boxes is:

225/21 = 10.7

It will take 11 robots to do the same job as the 15 humans

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You purchase 2 action figures per week. You have 48 action figures, which is 75% of the total number of action figures you need
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Answer:

64

Step-by-step explanation: In order to find the amount of action figures needed to complete your collection, you divide 48 by 75%. This gives us 64. The reason we divide, is because of inverse operations. If we are going to find 75% of 48, you would multiply 48 by .75. Since this is the opposite, we must divide it.

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10. A manufacturer wanted to know if more coupons would be redeemed if they were mailed to the
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Using the t-distribution, it is found that the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is, the mean is of 0, hence:

H_0: \mu = 0

At the alternative hypothesis, it is tested if the mean number is greater for females, that is, the mean is greater than 0, hence:

H_1: \mu > 0

<h3>What is the test statistic?</h3>

The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

In this problem, the parameters are given as follows:

\overline{x} = 1.5, \mu = 0, s = 4.75, n = 50.

Hence, the test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{1.5 - 0}{\frac{4.75}{\sqrt{50}}}

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Considering a <em>right-tailed test</em>, as we are testing if the mean is greater than a value, with a <em>significance level of 0.01 and 50 - 1 = 49 df</em>, the critical value is given by t^{\ast} = 2.4.

Since the test statistic is less than the critical value for the right-tailed test, the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

More can be learned about the t-distribution at brainly.com/question/26454209

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How to solve the problem
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