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3 years ago

Someone help me plz:

Mathematics

1 answer:

algol [13]3 years ago

7 0

Answer:

210,000

Step-by-step explanation:

I think this is correct because 35,000 times 6 equals 210,000

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Please Help!!! Braniest will be given

Lady bird [3.3K]

To solve this word problem, we will use the Pythagorean Theorem.

Pythagorean Theorem: a^2 + b^2 = c^2

Our side lengths are 10 and 24ft.

So, we can plug them in for a and b.

10^2 + 24^2 = c^2

100 + 576 = 676

Then, we need to find the square root of 676.

sqrt676) = 26

So, the missing length or the hypotenuse is 26 feet.

Therefore, we require 26 feet of string to measure the length of the hypotenuse in which the room is split in half.

4 0

3 years ago

Problem 10: A tank initially contains a solution of 10 pounds of salt in 60 gallons of water. Water with 1/2 pound of salt per g

AysviL [449]

Answer:

The quantity of salt at time t is $m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })$ , where t is measured in minutes.

Step-by-step explanation:

The law of mass conservation for control volume indicates that:

$\dot m_{in} - \dot m_{out} = \left(\frac{dm}{dt} \right)_{CV}$

Where mass flow is the product of salt concentration and water volume flow.

The model of the tank according to the statement is:

$(0.5\,\frac{pd}{gal} )\cdot \left(6\,\frac{gal}{min} \right) - c\cdot \left(6\,\frac{gal}{min} \right) = V\cdot \frac{dc}{dt}$

Where:

$c$ - The salt concentration in the tank, as well at the exit of the tank, measured in $\frac{pd}{gal}$ .

$\frac{dc}{dt}$ - Concentration rate of change in the tank, measured in $\frac{pd}{min}$ .

$V$ - Volume of the tank, measured in gallons.

The following first-order linear non-homogeneous differential equation is found:

$V \cdot \frac{dc}{dt} + 6\cdot c = 3$

$60\cdot \frac{dc}{dt} + 6\cdot c = 3$

$\frac{dc}{dt} + \frac{1}{10}\cdot c = 3$

This equation is solved as follows:

$e^{\frac{t}{10} }\cdot \left(\frac{dc}{dt} +\frac{1}{10} \cdot c \right) = 3 \cdot e^{\frac{t}{10} }$

$\frac{d}{dt}\left(e^{\frac{t}{10}}\cdot c\right) = 3\cdot e^{\frac{t}{10} }$

$e^{\frac{t}{10} }\cdot c = 3 \cdot \int {e^{\frac{t}{10} }} \, dt$

$e^{\frac{t}{10} }\cdot c = 30\cdot e^{\frac{t}{10} } + C$

$c = 30 + C\cdot e^{-\frac{t}{10} }$

The initial concentration in the tank is:

$c_{o} = \frac{10\,pd}{60\,gal}$

$c_{o} = 0.167\,\frac{pd}{gal}$

Now, the integration constant is:

$0.167 = 30 + C$

$C = -29.833$

The solution of the differential equation is:

$c(t) = 30 - 29.833\cdot e^{-\frac{t}{10} }$

Now, the quantity of salt at time t is:

$m_{salt} = V_{tank}\cdot c(t)$

$m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })$

Where t is measured in minutes.

7 0

3 years ago

Simplify the expression:<br> (2m + 1)(2) =

Dima020 [189]

4m+2

because 2mx2=4m and 1x2=2 so 4m+2

8 0

3 years ago

Read 2 more answers

Look at the figure. Which step should be taken next to construct a line through point R that is perpendicular to ST ?

Alika [10]

Answer:

where is the figure without figure how to find out

8 0

2 years ago

If f(x)=3x +10, g(3)=9 and f(-2)=g(-2) find the equation of the linear function g(x)

Agata [3.3K]

Answer:

The equation of the linear function g(x) is

g(x) = x + 6

Step-by-step explanation:

The step by step explanation is attached here.

Download rtf

5 0

3 years ago