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Lorico [155]
4 years ago
8

an omline newspaper had 350080 visitors in october 350489 visitors in november,and 305939 visitors in december.what is the order

of the mo th greatest to least numbrr of visitors?
Mathematics
2 answers:
Sauron [17]4 years ago
7 0
December October November
barxatty [35]4 years ago
7 0
1.December 305,939 2.November 350,489 3.October 350,080 
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I need you to help me solve this
Svet_ta [14]
For the expression to be factor-able the Discriminant  , has to be greater or equal to zero
ax^2 + cx + b = 0


c^2 - 4 ab >= 0 

(-3)^2 - 4 * 1 * b >= 0

9 - 4b >= 0

9 >= 4b

b <= 9/4  (2.25)

Pick any value in that range for ex:

0 , 2,  -3, -6

7 0
3 years ago
Two marbles are randomly drawn from a bag containing 3 purple, 1 blue, and 1 yellow marble. The first marble is blue and is not
liq [111]
I would say its 3/4 because there was only one blue and all together there is 4 now and the probability of picking a purple should be 3 out of 4.
4 0
3 years ago
drug sniffing dogs must be 95% accurate in their responses because their handlers don't want them to miss durgs and also don't w
GenaCL600 [577]

Answer:

95% Confidence interval:  (0.8449,0.9951)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 50

Number of times the dog is right, x = 46

\hat{p} = \dfrac{x}{n} = \dfrac{46}{50} = 0.92

95% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

Putting the values, we get:

0.92 \pm 1.96(\sqrt{\dfrac{0.92(1-0.92)}{50}})\\\\ = 0.92\pm 0.0751\\\\=(0.8449,0.9951)

(0.8449,0.9951) is the required 95% confidence interval for the proportion of times the dog will be correct.

7 0
3 years ago
Anyone know this answer?
damaskus [11]
La of sine:

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arcsinB or sin⁻¹ B = 64.5°, & sin (B°) = sin (180° - B°), then

sin(64.5) = sin(180°-64.5°) ==> B = 64.5° or 115.5°
6 0
3 years ago
You look at an ant under a magnifying glass. Find the actual length of the ant. The image of the ant is 8 times the ants actual
ella [17]
Divide 5.6 by 8 which is 0.7. Since the image of the ant is 8 times bigger we need to divide by 8 to make it actual size. 

The ant's actual length is 0.7 cm. 
5 0
3 years ago
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