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xeze [42]
1 year ago
7

Find h(3)+d(2) if h(x)= x-1 and d(x) = 7x + 3A.2 B.5 C.14 D.19

Mathematics
1 answer:
disa [49]1 year ago
8 0
\begin{gathered} h(x)=x-1 \\ d(x)=7x+3 \\ h(3)=3-1=2 \\ d(2)=7(2)+3=14+3=17 \\ h(3)+d(2)=2+17=19 \end{gathered}

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Plz somebody help. ^_^
pickupchik [31]

Answer:

sin θ =  15/17

Step-by-step explanation:

First we have to know how much the hypotenuse measures.

to take out the hypotenuse we will use pitagoras, with the following formula.

h^2 = c1^2 + c2^2

c1 = 8

c2 = 15

h^2 = 8^2 + 15^2

h^2 = 64 + 225

h = √ 289

h = 17

well to start we have to know the relationships between angles, legs and the hypotenuse.

a: adjacent

o: opposite

h: hypotenuse

sin θ = o/h

cos θ= a/h

tan θ = o/a

we want to know the sin of θ

sin θ = o/h

sin θ =  15/17

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Step-by-step explanation:

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