1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Juliette [100K]
2 years ago
9

I really need help!!!!

Mathematics
1 answer:
Zepler [3.9K]2 years ago
7 0
The answer should be B.) all you need to do is multiply the 1/2 by y and then do the same by 4. so your answer is 1/2y-2
You might be interested in
Can someone help me please.
34kurt

Answer:

c ?

Step-by-step explanation:

7 0
3 years ago
Help with this, i looked over the slides and they didn't help
FromTheMoon [43]

Answer:

its A

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
X3 − 6x2 − 7x + 60 = 0
inna [77]
An equation ........
4 0
3 years ago
List the fractions and decimals in order from least to greatest: -0.6,-5/8,-7/17,-0.72
zhuklara [117]
First, let's convert all of these numbers to decimal form:

(This will make it much easier to compare.)

- 0.6, - 0.625, - 0.4117, - 0.72

Now we can list them from least to greatest!

-0.4117, - 0.6, -0.625, -0.72

And don't forget to convert the selective decimals that we converted earlier back into fractions!

Therefore, the final list would be:
- 7/17, - 0.6, - 5/8, - 0.72

Hope this helps! 
3 0
3 years ago
. Use the quadratic formula to solve each quadratic real equation. Round
Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}, with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}

\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5

So B has two solutions of 5 and -1.5.

Now to C!

\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}

\frac{44}{8} = 5.5

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

4 0
3 years ago
Other questions:
  • What is the area of this parallelogram? ​
    9·1 answer
  • Calculate: 2.7·6.2–9.3·1.2+6.2·9.3–1.2·2.7<br> not pemdas. some shortcut method plz
    15·2 answers
  • Need help. <br><br> Enter an inequality that represents the graph in the box.
    9·1 answer
  • A tree stands 22 feet tall and is 382 feet from a building. The tree casts a shadow that is 40 feet long. How tall is the buildi
    8·1 answer
  • What is the area of this
    12·1 answer
  • Find the value of the variable and GH if H is between G and I. GI = 5b + 2, HI = 4b – 5, HI = 3
    11·1 answer
  • A rectangle has opposite sides that are parallel and congruent. What is the measure of each interior angle in a rectangle?
    9·1 answer
  • Write. varible expression to describe the rule for the sequence 8,10,12,14 then find the 100th term
    15·1 answer
  • Two dice are thrown together. what is the probability of obtaining a triangular number? ​
    11·1 answer
  • select the procedure that can be used to show the converse of the pythagorean theorem using side lenghths chosen from 6cm, 9cm,
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!