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2 years ago

11

Find the probability of rolling divisors of 24

1 answer:

Monica [59]2 years ago

4 0

Answer:

5/6 is the probability

Step-by-step explanation:

Factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24 and rolling a 6-sided die you can get 1, 2, 3, 4, 5, 6 so 5 is the only thing you can roll that isn't a factor of 24 so

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a boat is traveling at an average speed of 15 meters per second. how many kilometers per minute is the boat traveling?

lukranit [14]

We know that 1 meter is 0.001 km and that 1 minute is 60 seconds.
To transform 15m/s we into km/min we have to multiply 15 by 0.001 and multiply it by 60.
$15*0.001*60=0.0015*60=0.09 km/min$ - its the answer

4 0

3 years ago

Read 2 more answers

Solve each inequality. Graph the solution 3<5x-2<7

laiz [17]

Answer:

$2.976616664$

that tge answer

7 0

2 years ago

What is the answer to this equation? (picture attached)

SashulF [63]

Answer:

x = $\frac{42}{5}$

Step-by-step explanation:

Given

19 - $\frac{5x+6}{4}$ = 7 ( subtract 19 from both sides )

- $\frac{5x+6}{4}$ = - 12

Multiply both sides by - 4 to clear the fraction and the negative signs

5x + 6 = 48 ( subtract 6 from both sides )

5x = 42 ( divide both sides by 5 )

x = $\frac{42}{5}$

6 0

3 years ago

Save me the headache

maxonik [38]

$(9\sin2x+9\cos2x)^2=81$

Taking the square root of both sides gives two possible cases,

$9\sin2x+9\cos2x=9\implies\sin2x+\cos2x=1$

or

$9\sin2x+9\cos2x=-9\implies\sin2x+\cos2x=-1$

Recall that

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

If $\alpha=2x$ and $\beta=\dfrac\pi4$ , we have

$\sin\left(2x+\dfrac\pi4\right)=\dfrac{\sin2x+\cos2x}{\sqrt2}$

so in the equations above, we can write

$\sin2x+\cos2x=\sqrt2\sin\left(2x+\dfrac\pi4\right)=\pm1$

Then in the first case,

$\sqrt2\sin\left(2x+\dfrac\pi4\right)=1\implies\sin\left(2x+\dfrac\pi4\right)=\dfrac1{\sqrt2}$

$\implies2x+\dfrac\pi4=\dfrac\pi4+2n\pi\text{ or }\dfrac{3\pi}4+2n\pi$

(where $n$ is any integer)

$\implies2x=2n\pi\text{ or }\dfrac\pi2+2n\pi$

$\implies x=n\pi\text{ or }\dfrac\pi4+n\pi$

and in the second,

$\sqrt2\sin\left(2x+\dfrac\pi4\right)=-1\implies\sin\left(2x+\dfrac\pi4\right)=-\dfrac1{\sqrt2}$

$\implies2x+\dfrac\pi4=-\dfrac\pi4+2n\pi\text{ or }-\dfrac{3\pi}4+2n\pi$

$\implies2x=-\dfrac\pi2+2n\pi\text{ or }-\pi+2n\pi$

$\implies x=-\dfrac\pi4+n\pi\text{ or }-\dfrac\pi2+n\pi$

Then the solutions that fall in the interval $[0,2\pi)$ are

$x=0,\dfrac\pi4,\dfrac\pi2,\dfrac{3\pi}4,\pi,\dfrac{5\pi}4,\dfrac{3\pi}2,\dfrac{7\pi}4$

5 0

3 years ago

Read 2 more answers

What is the range of this function?

Lostsunrise [7]

Answer:

$c \: is \: correct \: \: \: the \: range \: is \: usually \: right \ \\ : and \: they \: are \: x \:$

5 0

3 years ago