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Eddi Din [679]
8 months ago
14

What is this line called that appears and disappears in the search box WILL MARK BRAINLIEST

Computers and Technology
1 answer:
Korvikt [17]8 months ago
3 0

Answer:

that is called the cursor.

Explanation:

A cursor is the position indicator on a computer display screen where a user can enter text.

Hope this helped!

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If x is an int, which of the following statements adds 5 to the current value of x and stores the new value back in x?
faust18 [17]
X += 5;

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6 0
3 years ago
I need help with these
solmaris [256]

Answer:

Choose internet is the right answer

7 0
2 years ago
i need a moderator or someone to answer this :/ why do i keep getting notifications that i have a new chat or a new answer/comme
Lyrx [107]

Answer:

It happens to me as well. Maybe check emails?  It could also be a bug.

Explanation:

4 0
3 years ago
Read 2 more answers
CODING TIME
Fynjy0 [20]

Answer:

food_list = ['rice', 'beans','yam', 'bread', 'pasta', 'cocoa','tea']

one_more = ['meat']

extend_list = food_list + one_more

print(extend_list)

Output : ['rice', 'beans','yam', 'bread', 'pasta', 'cocoa','tea', 'meat']

food_list.append('milk')

print(food_list)

Output : ['rice', 'beans','yam', 'bread', 'pasta', 'cocoa','tea', 'milk']

food_list.insert(0, 'cake')

print(food_list)

Output : ['cake', 'rice', 'beans','yam', 'bread', 'pasta', 'cocoa','tea']

flowers = ['rose', 'hibiscus', 'lily']

flowers.remove('rose')

print(flowers)

Output : ['hibiscus', 'lily']

To remove rose using pop()

flowers.pop(0)

Explanation:

The + operator and append method adds elements to the end of an existing list item.

The insert method adds element at the specified index

Remove method deletes element by stating the name of the element to be deleted while pop deletes element using the index value of the element.

7 0
2 years ago
The 7-bit ASCII code for the character ‘&’ is: 0100110 An odd parity check bit is now added to this code so 8 bits are trans
Alex787 [66]

Answer

First part:

The transmitted 8-bit sequence for ASCII character '&' with odd parity will be 00100110. Here leftmost bit is odd parity bit.

Second part:

The invalid bit sequence are option a. 01001000 and d. 11100111

Explanation:

Explanation for first part:

In odd parity, check bit of either 0 or 1 is added to the binary number as leftmost bit for making the number of 1s in binary number odd.

If there are even number of 1s present in the original number then 1 is added as leftmost bit to make total number of 1s odd.

If there are odd number of 1s present in the original number then 0 is added as leftmost bit to keep the total number of 1s odd.  

Explanation for second part:

A valid odd parity bit sequence will always have odd number of 1s.

Since in option a and d,  total number of 1s are 2 and 6 i.e. even number. Therefore they are invalid odd parity check bit sequences.

And since in option b and c, total number of 1s are 5 and 7 i.e. odd numbers respectively. Therefore they are valid odd parity check bit sequences.

7 0
3 years ago
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