Answer:
Array + 36.
Explanation:
The array contains the address of the first element or the starting address.So to find the address of an element we to add the size*position to the starting address of the array.Which is stored in the variable or word in this case.
There are 9 elements in the array and the size of integer is 4 bytes.So to access the last element we have to write
array + 4*9
array+36
Answer:
A and B
Explanation:
parsing with a rich grammar like TAG faces two main obstacles: low parsing speed and a lot of ambiguous syntactical parses.
Answer:
#include <iostream>
#include <time.h>
#include <string>
using namespace std;
int main(){
srand(time(NULL));
cout<<"Throw dice"<<endl;
int b =0;
int a=0;
a=rand()%6;
b=rand()%6;
for (int i =0;i<1;i++)
{cout<<"dice one: "<<a<<endl;}
for (int i =0;i<1;i++)
{cout<<"dice two: "<<b<<endl;}
if(a>b)
{cout<<"first dice won"<<endl;}
if(b>a)
{cout<<"second dice won"<<endl;}
else{cout<<"they are same"<<endl;
return main();
}
return 0;
}
Explanation:
/*best dice roll game just for you change it as you want but all necessary things are there/*
<span>b. false; unlike clip art, you cannot resize a photograph
</span>
Solution:
Users of an access point share the transmission capacity of the access point. The throughput a user gets is called the bits per seconds.
Thus this is the required answer.
