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mylen [45]
1 year ago
5

What is the molarity of a solution prepared by dissolving 3.50 mol nacl in enough water to make 1.50 l of solution?

Chemistry
1 answer:
nydimaria [60]1 year ago
4 0

Molarity of a solution prepared by dissolving 3.50 mol nacl in enough water to make 1.50 l of solution is 2.33 mol /L

<h3>What is Molarity?</h3>

Molarity is a physical quantity that describes the substance's number of moles available in the unit liter volume of the solution. A mole per liter is a measurable unit to explain molarity.

Number of moles of the NaCl is

np = 3.50 mol

The volume of the solution is np = 1.50 L

The expression for the molarity solution is cm = np/vp

At the value and get the above expression

Cm = 3.50/ 1.50

      = 2.33 mol /L

Thus the molarity of the solution is 2.33 mol /L

To know more about molarity related questions click

brainly.com/question/17138838

#SPJ4

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What is the specific heat of an unknown metal of 2.93 kcal of energy are required to raise the temperature of 183.4g sample of t
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Answer:

The specific heat of the unknown metal is 1.26*10⁻⁴ \frac{kcal}{g* C}

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat occurs when heat added or removed from a substance causes a temperature change in it and is calculated by:

Q = c * m * ΔT

Where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT (Tfinal - Tinitial) is the variation in temperature

In this case:

  • Q= 2.93 kcal
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Replacing:

2.93 kcal= c* 183.4 g*126.3 °C

Solving:

c=\frac{2.93 kcal}{183.4 g* 126.3 C}

c= 1.26*10⁻⁴ \frac{kcal}{g* C}

<u><em>The specific heat of the unknown metal is 1.26*10⁻⁴ </em></u>\frac{kcal}{g* C}<u><em></em></u>

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