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solmaris [256]
2 years ago
11

A kettle takes 3 minutes to boil. Calculate what part of an hour it is.​

Chemistry
2 answers:
Lelu [443]2 years ago
5 0

Answer:

soln,

=3×60

=180 answer

daser333 [38]2 years ago
3 0

Answer:

1/20

Explanation:

an hour is 60 minutes and its 3 minutes of an hour therefore its 3/60 hour  or 1/20 of an hour

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3 years ago
#5.) Explain why the rock cycle is referred to as a "cycle".
Natalka [10]
The rock cycle is referred to as cycle because it repeats over and over again. The definition of cycle is a series of events that are regularly related in the same order. So with the rock cycle they stay in the same order and repeat.
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5 0
3 years ago
Read 2 more answers
7. Convert 5.2 cm of magnesium (Mg) ribbon to mm of Mg ribbon.
Effectus [21]
<h3>Answer:</h3>

52 mm

<h3>Explanation:</h3>

We are given;

  • 5.2 cm of magnesium

Required to convert it to cm

We are going to use the appropriate conversion factor;

  • The units used to measure length include;

Kilometer(km)

10

Hectometer (Hm)

10

Decameter (dkm)

10

Meter(m)

10

Decimeter (dm)

10

Centimeter (cm)

10

Millimeter (mm)

Therefore; the appropriate conversion factor is 10mm/cm

Thus;

5.2 cm will be equivalent to;

= 5.2 cm × 10 mm/cm

= 52 mm

Therefore, the length of magnesium ribbon is 52 mm

7 0
2 years ago
Read 2 more answers
How is a gamete different from other types of cells in a person's body?
vagabundo [1.1K]
The human gametes differ from all the other cells in the body because the somatic cells have a complete set of chromosomes
6 0
3 years ago
Materials expand when heated. Consider a metal rod of length L0 at temperature T0. If the temperature is changed by an amount ΔT
marysya [2.9K]

Answer:

(a) The length at temperature 180°C is 40.070 cm

(b) The length at temperature 90°C is 64.976 inches

(c) L(T, α) = 60·α·T - 9000·α + 60

Explanation:

(a) The given parameters are

The thermal expansion coefficient, α for steel = 1.24 × 10⁻⁵/°C

The initial length of the steel L₀ = 40 cm

The initial temperature, t₀ = 40°C

The length at temperature 180°C = L

Therefore, from the given relation, for change in length, ΔL, we have;

ΔL = α × L₀ × ΔT

The amount the temperature changed ΔT = 180°C - 40°C = 140°C

Therefore, the change in length, ΔL, is found as follows;

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 40 × 140°C = 0.07 cm

Therefore, L =  L₀ + ΔL = 40 + 0.07 = 40.07 cm

The length at temperature 180°C = 40.07 cm

(b) Given that the length at T = 120°C is 65 in., we have;

The temperature at which the new length is sought = 90°C

The amount the temperature changed ΔT = 90°C - 120°C = -30°C

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 65 × -30°C = -0.024375 inches

The length, L at 90°C is therefore, L = L₀ + ΔL = 65 - 0.024375 = 64.976 in.

The length at temperature 90°C = 64.976 inches

(c) L = L₀ + ΔL  = L₀ +  α × L₀ × ΔT = L₀ +  α × L₀ × (T - T₀)

Therefore;

L = 60 +  α × 60 × (T - 150°C)

L = 60 + α × 60 × T - 9000 × α

L(T, α) = 60·α·T - 9000·α + 60

7 0
3 years ago
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