How would you calculate the molar mass of 2AgCl?

The balanced reaction equation for combustion of heptane, C7H16, is

Allisa [31]

Answer: m = 11.2 g C7H16

Explanation: First convert the mass of CO2 to moles. Then do the mole ratio between CO2 and C7H16 which is 7:1. Finally convert the moles of C7H16 to the mass of C7H16.

Solution attached.

3 0

3 years ago

Read 2 more answers

6. A 25.0-mL sample of potassium chloride solution was found to have a mass of 25.225 g.

Morgarella [4.7K]

Answer:

6. a. 5.53 (m/m) %; b. 0.7490M

7. 0.156M

Explanation:

6. In the solution of KCl, there are 1.396g of KCl in 25.225g of solution. As mass/mass percent is:

Mass solute / Mass solution * 100

The mass/mass percent of KCl is:

a. 1.396g KCl / 25.225g solution * 100

5.53 (m/m) %

b. Molarity is moles of solute per liters of solution:

Moles KCl -Molar mass: 74.55g/mol-:

1.396g KCl * (1mol / 74.55g) = 0.018726 moles KCl

Volume in liters: 25mL = 0.025L

Molarity:

0.018726 moles KCl / 0.025L = 0.7490M

7. 0.90% means 0.90g of NaCl in 100g of solution:

Moles NaCl -Molar mass: 58.44g/mol-:

0.90g NaCl * (1mol / 58.44g) = 0.0154 moles NaCl

Volume in Liters:

100g * (1mL / 1.01g) = 99mL = 0.099L

Molarity:

0.0154 moles NaCl / 0.099L =

0.156M

4 0

3 years ago

So before i have to do the science fair i have to write 5 questions that will lead me to a hypothesis my project is which substa

Gnom [1K]

Answer:

Explanation:

The best bet would just be to use filler questions, after all this is one of the least important parts.

Examples would be: Would blank melt ice faster because blank?

and so on

4 0

3 years ago

A blank and blank are examples of solids

galina1969 [7]

Dirt and a chair are examples if solids. Some more examples are tables chips and blankets.

5 0

3 years ago

A student titrated a solution containing 3.7066 g of an unknown Diprotic acid to the end point using 28.94 ml of 0.3021 M KOH so

uranmaximum [27]

Answer:

Molar mass of the diprotic acid is 424 grams

Explanation:

[hint: diprotic acid only contains 2 hydrogen protons]

Ionic equation:

${ \bf{2OH { }^{ - } _{(aq)} + 2H { }^{ + } _{(aq)}→ 2H _{2} O _{(l)} }}$

first, we get moles of potassium hydroxide in 28.94 ml :

${ \sf{1 \: l \: of \: KOH \: contains \: 0.3021 \: moles}} \\ { \sf{0.02894 \: l \: of \: KOH \: contain \: (0.02894 \times 0.3021) \: moles}} \\ { \underline{ = 0.008743 \: moles}}$

since mole ratio of diprotic acid : base is 2 : 2, moles are the same.

Therefore, moles of acid that reacted are 0.008743 moles.

${ \sf{0.008743 \: moles \: of \: acid \: weigh \: 3.7066 \: g}} \\ { \sf{1 \: mole \: of \: acid \: weighs \: ( \frac{1 \times 3.7066}{0.008743}) \: g }} \\ = { \underline{423.95 \: g \approx424 \: grams}}$

for the molar mass:

8 0

3 years ago