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lord [1]
2 years ago
13

Bharat types 20 words/min. How many words can he type in each length of time? a) 5 min b) 30 min c) 23 min

Mathematics
1 answer:
e-lub [12.9K]2 years ago
3 0

Bharat can type words in lengths of time as 100 words, 600 words, and 460 words in 5 minutes, 30 minutes, and 23 minutes respectively.

<h3>What are Arithmetic operations?</h3>

Arithmetic operations can also be specified by subtracting, dividing, and multiplying built-in functions.

* Multiplication operation: Multiplies values on either side of the operator

For example 12×2 = 24

Bharat types 20 words per minute which are given in the question.

To determine the number of words can he type in each length of time

We have to multiply the time by his typing speed.

The number of words that can be typed by Bharat in 5 minutes :

⇒ 20 × 5

⇒ 100

The number of words that can be typed by Bharat in 30 minutes :

⇒ 20 × 30

⇒ 600

The number of words that can be typed by Bharat in 23 minutes :

⇒ 20 × 23

⇒ 460

Therefore, He can type words in lengths of time as 100 words, 600 words, and 460 words in 5 minutes, 30 minutes, and 23 minutes respectively.

Learn more about Arithmetic operations here:

brainly.com/question/25834626

#SPJ1

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Solve the equation. Show your work and check your solution.<br> 4+4(x−2)=2(x+1)−x
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Answer:

x = 3/5

Step-by-step explanation:

4+4(x-2)=2(x+1)−x

Distribute

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Assuming that the heights of college women are normally distributed with mean 64 inches and standard deviation 1.5 inches, what
professor190 [17]

Answer:

15.74% of women are between 65.5 inches and 68.5 inches.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 64, \sigma = 1.5

What percentage of women are between 65.5 inches and 68.5 inches?

This percentage is the pvalue of Z when X = 68.5 subtracted by the pvalue of Z when X = 65.5.

X = 68.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{68.5 - 64}{1.5}

Z = 3

Z = 3 has a pvalue of 0.9987

X = 65.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{65.5 - 64}{1.5}

Z = 1

Z = 1 has a pvalue of 0.8413

So 0.9987 - 0.8413 = 0.1574 = 15.74% of women are between 65.5 inches and 68.5 inches.

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3 years ago
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Answer:

46°

Step-by-step explanation:

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